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Arisa [49]
3 years ago
6

What does the slope of the curve on a distance vs time graph represent?

Physics
1 answer:
Lilit [14]3 years ago
6 0

Slope of a curve Y plotted against X is mathematically given as

slope = \frac{dy}{dx}

now here we can see that if similarly graph is plotted against distance and time then slope is given as

slope = \frac{dx}{dt}

here we can say that above is ratio of small distance and very small interval of time.

so here we can say that this ratio of distance and time for very small interval of time is known as instantaneous speed of the object which is falling freely under gravity.

So here slope of the graph will represent the speed at a given instant.

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The atmosphere of Mercury and Mars are very thin. What effect does the thin atmosphere have on the temperature on the surface of
KengaRu [80]

Answer:

Very hot during the day and very cold at night.

Explanation:

Due to the thin atmosphere, they have very hot climate during the day time and very cold climate at night. This happens because they contain very low amounts of greenhouse gases. These gases retain the heat at night. The atmosphere also prevents excessive light and UV rays from entering. The thin  atmosphere leads to many asteroids and comets hitting the surface of the planet. On earth, these asteroids usually, burn up in the mesosphere layer of the atmosphere. These asteroid collisions cause massive fires. This in turn,  causes the temperature to increase during the day. During the night time, massive fires cannot burn due to the low temperature because of the lack of greenhouse gases.

3 0
2 years ago
The diagram below shows a circuit with a
kirill [66]

Answer:

15v

Explanation:

V = IR

= 0.3*50

= 15V.

I HOPE IT'S HELPFUL

4 0
2 years ago
A parcel has a mass of 500 g .calculate its weight (assume the gravitational field strength is 10 N/Kg
Effectus [21]

Answer:

5N

Explanation

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5 0
3 years ago
When in orbit, astronauts experience weightlessness what is this caused by?
erica [24]

no gravity or dark matter

4 0
3 years ago
Read 2 more answers
A 5.5kg radio is pushed across the table. If the acceleration is 5m/s to the right, find the net force exerted on the radio.
Sholpan [36]

Answer:

Net force exerted on the radio is 27.5 Newton.

Given:

Mass = 5.5 kg

Acceleration = 5 \frac{m}{s^{2} }

To find:

Force exerted on the radio = ?

Formula used:

F = ma

Where F = net force

m = mass

a = acceleration

Solution:

According to Newton's second law of motion,

F = ma

Where F = net force

m = mass

a = acceleration

F = 5.5 × 5

F = 27.5 Newton

Hence, Net force exerted on the radio is 27.5 Newton.


4 0
3 years ago
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