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liubo4ka [24]
3 years ago
10

Earth's atmosphere traps energy from the sun which is a direct result of the trapping of energy by Earth's atmosphere?

Physics
1 answer:
Alik [6]3 years ago
3 0
Heat increase causing global warming causing high sea levels
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You find yourself in a place that is unimaginably hot and dense. A rapidly changing gravitational field randomly warps space and
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You find yourself in a place that is unimaginably <u>hot and dense</u>. A r<u>apidly changing</u><u> gravitational field</u><u> </u>randomly warps space and time. Gripped by these huge fluctuations, you notice that there is but a single, unified force governing the universe, you are in the early universe before the Planck time.

<h3>What is Planck time?</h3>

The Planck time is approximately<u> 10^-44 seconds</u>. The smallest time interval, or "zeptosecond," that has so far been measured is <u>10^-21 seconds</u>. A photon traveling at the speed of light would need one Planck time <u>to traverse a distance of one </u><u>Planck length</u>.

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2 years ago
A proton is initially at rest. After some time, a uniform electric field is turned on and the proton accelerates. The magnitude
marusya05 [52]

Answer:

a) 8.83*10⁵ m/s  b) 2.80*10⁶ m/s

Explanation:

a) Assuming no other forces acting on the proton, the acceleration on it is produced by the electric field.

By definition, the  force due to the electric field is as follows:

F = q*E = e*E (1)

where e is the elementary charge, the charge carried by only one proton, and is e = 1.6*10⁻¹⁹ C.

According to Newton's 2nd law, this force is at the same time, the product of the mass of the proton, times the acceleration a:

F = mp*a (2)

From (1) and(2), being left sides equal, right sides must be equal too:

F = e*E = mp*a

Solving for a:

a = \frac{e*E}{mp} =\frac{1.6e-19C*1.36e5N/C}{1.67e-27kg} =1.3e13 m/s2

⇒ a = 1.3*10¹³ m/s²

As we have the value of a (which is constant due to the field is uniform), the displacement x, and we know that the initial velocity is 0, in order to get the value of the speed, we can use the following kinematic equation:

vf^{2} -vo^{2} = 2*a*x

Replacing by v₀ = 0, a= 1.3*10¹³ m/s² and  x = 0.03 m, we can find vf as follows:

vf =\sqrt{2*(1.3e13 m/s2)*0.03m} = 8.83e5 m/s

⇒ vf = 8.83*10⁵ m/s

b) We can just repeat the equation from above, replacing x=0.03 m by x=0.3 m, as follows:

vf =\sqrt{2*(1.3e13 m/s2)*0.3m} = 2.80e6 m/s

⇒ vf = 2.80*10⁶ m/s

4 0
3 years ago
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