One of the postulates of bohr's atomic model of a moving electron is that angular momentum of a moving electron is quantized. Ex
1 answer:
The angular momentum of an electron in the third Bohr orbit of a hydrogen atom is given by mvr=3h÷2π
<h3>What is momentum?</h3>Momentum is defined as the amount of motion occurring in something that is moving, or the force that drives something forward to keep it moving.
Bohr never assumed stable electronic orbits with the electronic angular momentum quantized as
l=mvr =
Quantization of angular momentum means that the radius of the orbit and the energy will be quantized as well.
Bohr assumed that the discrete lines seen in the spectrum of the hydrogen atom were due to transitions of an electron from one allowed orbit/energy to another.
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Here, we have to get the number of atoms present in the 100 plane of the FCC crystal lattice.
There will be 2 atoms in 100 plane of FCC crystal lattice.
In the face centered crystal (FCC) lattice there are atoms at each corner of the cube and each are shared by 4 another atoms. And an atom is present at the face of the crystal.
For the 100 plane of the Miller indices the intercepts are a, ∞, ∞ or 2a, ∞, ∞.
Thus, for the 4 atoms of the corner at the cube shared by 4 other atoms will contribute, 4 × = 1 and the un-shared atoms at the face will contribute another 1, which make the total atom 1 + 1 = 2.