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monitta
2 years ago
13

One of the postulates of bohr's atomic model of a moving electron is that angular momentum of a moving electron is quantized. Ex

plain its meaning and calculate the angular momentum of third orbit (i.e n=3)
Chemistry
1 answer:
oksano4ka [1.4K]2 years ago
5 0

The angular momentum of an electron in the third Bohr orbit of a hydrogen atom is given by mvr=3h÷2π

<h3>What is momentum?</h3>

Momentum is defined as the amount of motion occurring in something that is moving, or the force that drives something forward to keep it moving.

Bohr never assumed stable electronic orbits with the electronic angular momentum quantized as

l=mvr = \frac{nh}{2pi}

Quantization of angular momentum means that the radius of the orbit and the energy will be quantized as well.

Bohr assumed that the discrete lines seen in the spectrum of the hydrogen atom were due to transitions of an electron from one allowed orbit/energy to another.

Learn more about momentum here:

https://brainly.in/question/38837394

#SPJ1

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For the reaction show below determine the rate law. H2SO3(aq) + 6I-(aq) + 4H+(aq) → S(s) + 2I3- + 3H2O (l) In the presence of a
alekssr [168]

Answer:

Please see the attached picture for the complete answer.

Explanation:

7 0
3 years ago
What is the percent yield for a process in which 10.4g of CH3OH reacts and 10.1 g of CO2 is formed
monitta

Answer:

A. 70.7%

Explanation:

In the first step lets compute the molar mass of CH₃OH and CO

Molar Mass of CH₃OH =  1(12.01 g/mol) + 4(1.008 g/mol) +1(16.00 g/mol)

                                     = 32.042 g/mol

Molar Mass of CO₂      = 1(12.01 g/mol) + 2(16.00 g/mol)  

                                     = 44.01 g/mol

                                   

Mass of only one reactant i.e. CH₃OH is given so  it must be the limiting reactant. Next, the theoretical yield is calculated directly as follows:

Given mass of CH₃OH is 10.4 g. So we have:

                                     10.4g CH₃OH

Convert grams of CH₃OH to moles of CH₃OH utilizing molar mass of CH₃OH as:

                          1 mol CH₃OH / 32.042 g CH₃OH

Convert CH₃OH to moles of CO₂ using mole ratio as:

                             2 mol CO₂ / 2 mol CH₃OH

Convert moles of  CO₂ to grams of  CO₂ utilizing molar mass of  CO₂ as:

                           44.01 g/mol CO₂ / 1 mol CO₂

Now calculating theoretical yield using above steps:

[ 10.4 g CH₃OH ]  [1 mol CH₃OH / 32.042 g CH₃OH ]  [2 mol CO₂ / 2 mol CH₃OH]  [44.01 g/mol CO₂ / 1 mol CO₂]

Multiplication is performed here. We are left with 10.4 and 44.01 g CO₂ from numerator terms in the above equation and 32.042 from denominator terms after cancellation process of above terms. So this equation becomes:

= ( 10.4 ) ( 44.01 ) g CO₂ / 32.042

= 457.704/32/042

=  14.28 g CO₂

Theoretical yield =  14.28 g CO₂  

Finally compute the percent yield for a process in which 10.4g of CH₃OH reacts and 10.1 g of CO₂ is formed:

percent yield = (actual yield / theoretical yield) x 100

As we have calculated theoretical yield which is 14.28 g CO₂ and actual yield is 10.1 g CO₂ So,

percent yield = (10.1 g CO₂ / 14.28 g CO₂) x 100%

                       = 0.707 x 100%

                       = 70.7 %

Hence option A 70.7% yield is the correct answer.

8 0
3 years ago
What is the volume in cubic centimeters of a tablet weighing 210 mg
Sav [38]

Answer:

1mg=0.001

210

210×0.001÷1

=0.21

3 0
3 years ago
What is the molarity of a solution that contains 2 moles of solute in 4 liters of solution?
Nitella [24]
The simple formula is C = n/V
n = mols
C = Concentration or Molarity
V = Volume in Liters.

n = 2
V = 4
C = 2 / 4
C = 0.5 mol/Litre

8 0
3 years ago
Is cool-aid a element ,compound or mixture?
Cerrena [4.2K]
Kool-aid is a mixture.
6 0
3 years ago
Read 2 more answers
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