The balanced chemical reaction for the substances given would be as follows:
Zn + 2HCl = ZnCl2 + H2
We are given the amounts of the reactants used in the reaction. We use these amounts to determine which is the limiting and excess reactant. We do as follows:
10 g Zn (1 mol / 65.38 g) = 0.1530 mol
10 g HCl (1 mol / 36.46 g) = 0.2743 mol
From the the stoichiometric ratio which is 1 is to 2, the limiting reactant would be hydrochloric acid and the excess would be zinc metal.
Mass of zinc that remains = 0.1530 - (0.2743 / 2) = 0.0159 g Zn
Answer: In order to help the plants reproduce, flowers that are bright in color are meant to attract birds, bees and other insects. In the genetics of a flower, bright or dull colors are set in
Explanation:
Answer:
The atom is oxidized is Ca.
Explanation:
- The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
- The oxidation process is the process in which electrons are lost and produce positively charged ions.
- The reduction process is the process in which electrons is gained and negatively charge ions are produced.
- In the reaction of chlorine with calcium:
<em>Ca + Cl₂ → CaCl₂,</em>
Ca loses 2 electrons and is oxidized to Ca²⁺. (Ca <em>→</em> Ca²⁺ + 2e).
Cl is gains 2 electrons in "Cl₂, oxidation state zero" and is reduced to Cl⁻. (Cl₂ + 2e <em>→</em> 2Cl⁻).
The answer is enough solvent to make 1.00 L of solution. Since molarity is the number of moles of solute in one liter of solution, adding 0.500 mole solute to one liter solvent might not result to a solution with one liter total volume. Less than one liter solvent is first added to dissolve 0.500 mole solute and then the solution is carefully filled with more solvent until the solution reaches to one liter total volume. Hence, the resulting solution is a 0.500M concentration.
Carbon to carbon bond is nonpolar covalent since the difference of their electronegativity’s is 0. Carbon has an electronegativity of 2.5. 2.5 - 2.5 is 0 making the bond between those two atoms nonpolar covalent. I hope I answered your question.