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34kurt
3 years ago
12

Which of the following would you expect to form an ionic bond when combined?

Chemistry
1 answer:
Setler79 [48]3 years ago
3 0
2. Mg and Cl would be the best answer as Mg is likely to give its two away and Cl is likely to take one so it would be Cl2Mg.
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In a two-step synthesis, C6H11Br is converted into C6H12O. From the structure of the product, molecular formula of the starting
tamaranim1 [39]

Answer:

See explanation below

Explanation:

The question is incomplete. However in picture 1, you have the starting materials and the structure of the product, which you miss in this part.

Now, in picture 2, you have the starting reactant and the product, and the mechanism that is taking place here.

First, all what we have here is an acid  base reaction. In the first step, we are using the acid medium to convert the reactant into an alcohol. The bromine there, is not leaving the molecule yet, because it's neccesary for the next step. The starting reactant is an alkene, in that way, we can convert the reactant in the first step into a secondary alcohol. In other words, the first reaction is a alkene hydration.

In the second step, we use a strong base. You may say this is a strong nucleophile and will do a Sn2 reaction to form another alcohol there, but it's not the case, because, before any kind of reaction happens, the priority here is always the acid base, so the base will react with the acidic hydrogen. In this case, it will substract an hydrogen from the OH. When this happens, the lone pair will do an auto condensation here, and attacks the bromine in the molecule. In this way, the molecule will become a cyclomolecule, and that way it form the final product.

See picture 2, for mechanism

8 0
3 years ago
At 400 K, the equilibrium constant for the reaction Br2 (g) + Cl2 (g) ↔ 2BrCl (g) is Kp = 7.0. A closed vessel at 400 K is charg
xz_007 [3.2K]

Answer:

(a) The equilibrium partial pressure of BrCl (g) will be greater than 2.00 atm.

Explanation:

Q is the coefficient of the reaction and is calculated the same of the way of the equilibrium constant, but using the concentrations or partial pressures in any moment of the reaction, so, for the reaction given:

Q = (pBrCl)²/(pBr₂*pCl₂)

Q = 2²/(1x1)

Q = 4

As Q < Kp, the reaction didn't reach the equilibrium, and the value must increase. As we can notice by the equation, Q is directly proportional to the partial pressure of BrCl, so it must increase, and be greater than 2.00 atm in the equilibrium.

The partial pressures of Br₂ and Cl₂ must decrease, so they will be smaller than 1.00 atm. And the total pressure must not change because of the stoichiometry of the reaction: there are 2 moles of the gas reactants for 2 moles of the gas products.

Because is a reversible reaction, it will not go to completion, it will reach an equilibrium, and as discussed above, the partial pressures will change.

5 0
3 years ago
Compare and contrast the Andes Mountains and the Rocky Mountains. How are they formed? What consumers and producers are in each?
Naily [24]

Answer:

ummm i need help too lol

Explanation:

7 0
2 years ago
What is the hydrogen ion concentration of a substance with a pH of 4.5?​
FrozenT [24]

Answer:

The hydrogen ion concentration of the substance is 3.16*10⁻⁵ M

Explanation:

pH is a parameter used to measure the degree of acidity or alkalinity of a substance. The pH is calculated as the negative logarithm (base 10) of the concentration of hydronium ions [H₃O⁺] or hydrogen ions [H⁺].

pH= - log [H₃O⁺]= - log [H⁺]

Values ​​on the pH scale range from 0 to 14, where pH equal to 7 is neutral, below 7 is acidic and above 7 is basic.

In this case, pH= 4.5

So:

4.5= - log [H⁺]

Solving:

[ H⁺]= 10⁻⁴ ⁵

[H⁺]= 3.16*10⁻⁵ M

The hydrogen ion concentration of the substance is 3.16*10⁻⁵ M

7 0
3 years ago
The first-order decomposition of cyclopropane has a rate constant of 6.7 x 10-4 s-1. if the initial concentration of cyclopropan
vaieri [72.5K]
The first order rate law has the form: -d[A]/dt = k[A] where, A refers to cyclopropane. We integrate this expression in order to arrive at an equation that expresses concentration as a function of time. After integration, the first order rate equation becomes:

ln [A] = -kt + ln [A]_o, where,

k is the rate constant
t is the time of the reaction
[A] is the concentration of the species at the given time
[A]_o is the initial concentration of the species

For this problem, we simply substitute the known values to the equation as in:

ln[A] = -(6.7 x 10⁻⁴ s⁻¹)(644 s) + ln (1.33 M) 

We then determine that the final concentration of cyclopropane after 644 s is 0.86 M.
5 0
3 years ago
Read 2 more answers
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