Answer:
5.1 days
Step-by-step explanation:
Given in the question,
initial amount of substance = 34 grams
k-value = 0.137
To find the half life of this substance we will use following formula
here N(0) is initial amount of substance
t is time in days
Plug values in the formula
1/2 = e^{-0.137t}
Take logarithm on both sides
ln(1/2) = ln( e^{-0.137t})
ln(1/2) = -0.137t
t = ln(1/2) / -0.137
t = 5.059
t ≈ 5.1 days (nearest to tenths)
-8 - 7x is the factored version.
Answer:
d
Step-by-step explanation:
I already did this before
Here are some answer i can think of: 2-10$ 1-5$ 2-1$, 6-5$ 2-1$, 27-1$, 1-10$ 3-5$ 2-1$
There are ten time slots for these appointments. For the first time slot, there are 15 different students that can fill the slot. Next appointment, there are only 14 possible students since we already saw one. This goes on and on, 15 x 14 x 13... for 10 different time slots.
<span>15 x 14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 = 10,897,286,400
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