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pochemuha
3 years ago
8

How many formula units make up 25.8g of magnesium chloride (MgCl2)? Express the number of formula units numerically.

Chemistry
1 answer:
Verdich [7]3 years ago
8 0

Answer:

Explanation:

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Your lab partner told you that he measured out 25.0 mL of the unknown acid solution. But he actually went above the line on the
Sav [38]

Answer:

Final calculated molarity of the unknown acid be  lower than the actual concentration.

Explanation:

Volume required unknown acid = V= 25.0 mL

Volume actually measure was more than V that is = V'

V' > V

Molarity of the solution is the moles of compound in 1 Liter solutions.

Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}

As we can see from the formula that molarity is inversely proportional to the volume of the solution.

Molarity\propto \frac{1}{Volume}

  • Molarity of solution decreases with increase in volume
  • Molarity of solution Increases with decrease in volume.

We have added more volume than required which will be increase the volume of solution and the molarity of the solution will lower than the actual value.

6 0
3 years ago
What is the main type of energy in an iphone charging cable?
ki77a [65]

Answer: You're converting electrical energy from the wall outlet into chemical energy inside the battery, plus a bit of wasted heat energy, since battery charging is less than 100% efficient.

Explanation:

3 0
3 years ago
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In which situation might a forensic scientist decide to collect fiber evidence from a crime scene?
ololo11 [35]

Answer: C

Explanation:

C just because the other choices dont really make sense. They use these fibers as a way to see what clothes, shoe strings, carpets, etc was there it help identify a person at the scene. Hope this helps!!

8 0
2 years ago
For the reaction: N2(g) + 2 O2(g) ⇌ 2 NO2(g), Kc = 8.3 × 10-10 at 25°C. What is the concentration of N2 gas at equilibrium when
KATRIN_1 [288]

Answer: Concentration of N₂ is 4.8.10^{9} M.

Explanation: K_{c} is a constant of equilibrium and it is dependent of the concentrations of the reactants and the products of a balanced reaction. For

N2(g) + 2 O2(g) ⇄ 2 NO2(g)

K_{c} = \frac{[NO2]^{2} }{[N2][O2]^{2} }

From the question concentration of NO2 is twice of O2:

[NO2] = 2[O2]

Substituting this into K_{c}:

K_{c} = \frac{[2O2]^{2} }{[N2][O2]^{2} }

8.3.10^{-10} = \frac{4O2^{2} }{[N2].O2^{2} }

[N2] = \frac{4O2^{2} }{8.3.10^{-10}.O2^{2}  }

[N2] = \frac{4}{8.3.10^{-10} }

[N2] = 4.8.10^{9}

The concentration of N2 in the equilibrium is [N2] = 4.8.10^{9}M.

6 0
3 years ago
What are the oxidation numbers for groups 1-18 (skip groups 3-12)
Brilliant_brown [7]
Group 1: +1
Group 2: +2
Group 13: +3
Group 14: +4
Group 15: -3
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Group 17: -1
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2 years ago
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