Answer:
15.06 × 10²³ atoms of Li
Explanation:
Given data:
Number of moles of Li = 2.5 mol
Number of toms of Li = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For 2.5 mol of Li:
1 mole of lithium = 6.022 × 10²³ atoms of Li
2.5 mol × 6.022 × 10²³ atoms of Li / 1 mol
15.06 × 10²³ atoms of Li
The 2,4 and 5 positions are accessible for nitration of 1,3‑dimethylbenzene. The final product is shown in the image attached.
<h3>What is nitration?</h3>
Nitration is a type of reaction in which the nitro group (-NO2) is introduced to an aromatic ring. We have to note that in the compound 1,3‑dimethylbenzene, the 2,4 and 5 positions are accessible for nitration as shown.
Hence, the nitration of 1,3‑dimethylbenzene occurs as shown in the image attached with the compound shown being the major product.
Learn more about nitration: brainly.com/question/5346392
Thousands of cells that are located within the <span>tissue</span>
Answer:
The purpose of using a chemical equation is to keep track of elements and the number of atoms of each of the elements on each side of the equation. ... They use symbols and formulas to show the chemical reaction so that chemical names do not need to be written out.
Answer:
Explanation:
To calculate the reduced mass of nitrogen molecule = Mn x Mn/ Mn + Mn
Mn = atomic mass of Nitrogen = 14.00
reduced mass = 14 x 14 /14 + 14 = 7
Similarly for HCl; reduced mass for a hydrogen chloride molecule = Mh x Mcl/Mh + Mcl
where Mh = atomic mass of hydrogen = 1.008
Mcl = atomic mass of chrorine = 34.97
reduced mass for HCl = 1.008 x 34.97 /1.008 + 34.97
= 0.97
