Answer:
155.17N.
Explanation:
The magnitude of the net force is expressed as;
F = mv²/r where;
m is the mass
v is the velocity of the airplane
r is the radius of the loop
Given
m = 95kg
v = 70m/s
r = 3km = 3000m
Required
Magnitude of the net force
F = 95*70²/3000
F = 95*4900/3000
F = 95*49/30
F = 4655/30
F = 155.17N
Hence the magnitude of the net force on the 95 kg pilot at the bottom of this loop is 155.17N.
Answer:
Ampere
Explanation:
The ampere is the unit of measurement in the international system. Its equal to a coulomb/second. It can be describe as the rate of charges flowing throught a conductor
Answer:
The cloud moves 9050 meters to the east in 12.5 minutes.
Explanation:
Let suppose that mass of the cloud is negligible. meaning that effects of gravity are negligible and that altitude of the cloud remains constant. If the cloud drifts at constant velocity, travelled distance is defined by following formula:
(1)
Where:
- Velocity, in meters per second.
- Time, in seconds.
If we know that and , then the travelled distance after 12.5 minutes is:
The cloud moves 9050 meters to the east in 12.5 minutes.
Answer:
a)n= 3.125 x electrons.
b)J= 1.515 x A/m²
c) =1.114 x m/s
d) see explanation
Explanation:
Current 'I' = 5A =>5C/s
diameter 'd'= 2.05 x m
radius 'r' = d/2 => 1.025 x m
no. of electrons 'n'= 8.5 x
a) the amount of electrons pass through the light bulb each second can be determined by:
I= Q/t
Q= I x t => 5 x 1
Q= 5C
As we know that: Q= ne
where e is the charge of electron i.e 1.6 x C
n= Q/e => 5/ 1.6 x
n= 3.125 x electrons.
b) the current density 'J' in the wire is given by
J= I/A => I/πr²
J= 5 / (3.14 x (1.025x )²)
J= 1.515 x A/m²
c) The typical speed'' of an electron is given by:
=
=1.515 x / 8.5 x x |-1.6 x |
=1.114 x m/s
d) According to these equations,
J= I/A
= =
If you were to use wire of twice the diameter, the current density and drift speed will change
Increase in the diameter increase the cross sectional area and decreases the current density as it has inverse relation.
Also drift velocity will decrease as it is inversely proportional to the area