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Soloha48 [4]
3 years ago
5

Tyyyyyyyyyyyyyyyyyyyyyyyy​

Physics
2 answers:
andreyandreev [35.5K]3 years ago
5 0
Tyyyyyyyyyyyyyy for what
Aliun [14]3 years ago
4 0

Answer:

hub9hybygbgybgybgygybsbgydgbydxbgbyxdgbyxdyggdxygbyxdgybzgbydbgyzsbgydgbyzdgxbybgydzs

Explanation:

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An unknown substance has a mass of 11.9 g . When the substance absorbs 1.071×102 J of heat, the temperature of the substance is
Mashcka [7]

Answer: The most likely identity of the substance is iron.

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=1.071\times 10^2 Joules

m= mass of substance = 11.9 g

c = specific heat capacity = ?

Initial temperature of the water = T_i = 25.0°C

Final temperature of the water = T_f  = 45.0°CChange in temperature ,\Delta T=T_f-T_i=(45-25)^0C=20^0C

Putting in the values, we get:

1.071\times 10^2=11.9\times c\times 20^0C

c=0.45J/g^0C

The specific heat of 0.45 is for iron and thus the substance is iron.

3 0
4 years ago
What is one property of a suspension that is different from that of a solution or a colloid?
Step2247 [10]

Answer:

A

Explanation:

If left to rest it will separate.  

3 0
3 years ago
What is the theorem that says that impulse equals change in momentum
Marysya12 [62]
The impulse-momentum theorem

8 0
3 years ago
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Please help me easy question just need help
Nesterboy [21]

Answer:

what is Jose potential energy

7 0
3 years ago
Calculate the average travel time for each distance, and then use the results to calculate.
Eddi Din [679]

The average time that it takes for the car to travel the first 0.25m is 2.23 s

The average time that it takes for the car to travel the first 0.25 m is given by:

t=\frac{2.24 s+2.21 s+2.23 s}{3}=2.227 s \sim 2.23 s

The average time to travel just between 0.25 m and 0.50 m is 0.90 s

First of all, we need to calculate the time the car takes in each trial to travel between 0.25 m and 0.50 m:

t_1 = 3.16 s - 2.24 s=0.92 s\\t_2 = 3.08 s- 2.21 s=0.87 s\\t_3 =3.15 s- 2.23 s=0.92 s

Then, the average time can be calculated as

t=\frac{0.92 s+0.87 s+0.92 s}{3}=0.90 s

Given the time taken to travel the second 0.25 m section, the velocity would be 0.28 m/s

The velocity of the car while travelling the second 0.25 m section is equal to the distance covered (0.25 m) divided by the average time (0.90 s):

v=\frac{d}{t}=\frac{0.25 m}{0.90 s}=0.28 m/s

8 0
3 years ago
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