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3 years ago

A sound wave has a frequency of 192Hz and travels the length of a football field, 91.4m in 0.267s. What is the period?

Physics

1 answer:

Vinvika [58]3 years ago

6 0

Answer:1/192 seconds

Explanation:

Period=1÷frequency

Period=1÷192

Period=1/192 seconds

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Ratling [72]

The answer was is B

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2 years ago

How do you know whether to put a nine or a 10 in front of the number on the weather station

3241004551 [841]

If the air pressure on the station model is 500 or more, place a 9 in front of this number. If the pressure number on the station is less than 500 add a 10 in front of this number.

Good luck :)

7 0

2 years ago

Objects 1 and 2 attract each other with a electrostatic force of 72.0 units. if the charge of object 1 is halved, then the elect

vodka [1.7K]

Objects 1 and 2 attract each other with an electrostatic force of 72.0 units. if the charge of object 1 is halved, then the electrostatic force is 36.0 units

Let's understand the answer

The electrostatic force is the force that exists between two charged particles which is given by:

$F = K\frac{Q_{1}Q_{2}}{r^{2}}$

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the distance between the charges

In this problem, the charge of object 2 is doubled, so

$F = K\frac{\frac{Q_{1}}{2} Q_{2}}{r^{2}}$

$F = \frac{K}{2} \frac{Q_{1} Q_{2}}{r^{2}}$

$F = \frac{F_{initial}}{2}$

So, the electrostatic force will be halved.

Since as the initial electrostatic force is

F = 72.0 units

the new force will be

72/2 = 36 units

Learn more about electrostatic force here

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8 0

1 year ago

Using a slotted line, the following results were obtained:

MAVERICK [17]

Answer:

$Z_L=67 - j16.4$ Ω

Explanation:

Given that

d(min,0)= 4 cm

d(min,1)= 14 cm

Voltage standingwave ratio = 1.5

Zo = 50 Ω

We know that

d(min,1) - d(min,0) = λ/2

Now by putting the values

14 - 4 = λ/2

λ = 20 cm

We also know that

β=2π/λ

β=2π/0.2 = 10π rad/m

So we can say that

θr= 2β d(min,n) - (2 n + 1)π rad

θr=2×10π ×0.04 −π = -0.2 π rad

We know that

π rad = 180 °

θr= = -0.2 π rad= -36 °

We know that

$\Gamma =\dfrac{S-1}{S+1}$

Here S= 1.5

$\Gamma =\dfrac{S-1}{S+1}$

$\Gamma =\dfrac{1.5-1}{1.5+1}$

$\Gamma =0.2$

$Z_L=Z_o\dfrac{1+\Gamma }{1-\Gamma }$

by putting the values

$Z_L=50\times \dfrac{1+0.2e^{-j36^{\circ}} }{1-0.2e^{-j36^{\circ}} }$

$Z_L=67 - j16.4$ Ω

6 0

3 years ago

Engineers are designing a curved section of a highway. If the radius of curvature of the curve is 173 m, at what angle should th

egoroff_w [7]

Answer: The angle Ø = 26

Explanation:

The weight and the normal force of the road are the only two external forces acting on the car. A frictionless surface can only exert a force that is perpendicular to the surface. This is a normal force.

Since the car does not leave the surface of the road, the vertical components of the two external forces must be equal in magnitude and opposite in direction. Whereas ;

Horizontal component = centripetal force. While

The vertical component = Mg

Revolving the two components gives: tanØ = V^2/rg

Please find the attached file for the solution

8 0

2 years ago