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Likurg_2 [28]
3 years ago
13

Explain the necessity of smoothing the output voltage before applying it to a transistor

Physics
1 answer:
ra1l [238]3 years ago
6 0

In simple words, smoothing can be defined as the circuit which is done to eliminate the ripple from the yield of a direct current power supply.

<u>Explanation:</u>

<u>Necessity of smoothing:</u>

  • Smoothing can be also applied in the form of a capacitor that acts to decrease or level out variations in a signal. And these capacitors are mostly used after power supply in voltage.
  • The yield DC voltage of a half-wave rectifier provided in the figure of a sinusoidal wave.
  • In a method to provide a constant DC voltage from a corrected AC source, a filter or smoothing circuit is required.

<u></u>

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Describe a situation in which you exert a force on something and it does not move. Identify the action force and the reaction fo
goldfiish [28.3K]

Answer:

Please find the answer in the explanation.

Explanation:

To describe a situation in which you exert a force on something and it does not move, you need to Identify the action force and the reaction force, the relative size of the forces, and the objects they act on.

The magnitude of the static friction between the object and the ground is larger than the magnitude of the force applied.

The object will not move if the magnitude of the static friction is greater than the magnitude of the force applied.

The action force is the force applied while the reaction force is equal to the frictional force between the object and the ground.

3 0
3 years ago
Suppose you push a toy train with a force of 3 N east. The train has a mass of 0.5 kg. What is its acceleration?
Sergeu [11.5K]
The answer u are looking for is not a b or d it is c <span />
8 0
4 years ago
you hold a metal block of mass 40 kg above your head at a height of 2 m how much work is done bu gravity if you let the block fa
zzz [600]

Answer:

784 J

Explanation:

Work is force times distance.

W = Fd

W = mgd

W = (40 kg) (9.8 m/s²) (2 m)

W = 784 J

8 0
4 years ago
Near the poles, how does the amount of incoming solar radiation generally compare with the amount of outgoing terrestrial radiat
BlackZzzverrR [31]

Answer:

Is less in comparison with the rest of the Earth.

Explanation:

In poles now we have the magnetic centers of the planet, this will make that the magnetic field that is produced, can protect the planet from the radiation of cosmos. Magnetic field is also responsible of getting together the ionized particles that come from universe and they are ions, in this way they appear as an  a boreal or austral aurora.

8 0
3 years ago
A nonconducting ring with a radius of 11.5 cm is uniformly charged with a total positive charge of 10.0 µC. The ring rotates at
zhuklara [117]

Answer:

B=1.21*10^{-10}T

Explanation:

The magnitude of the magnetic field on the axis of the ring is given by:

B=\frac{\mu_0 IR^2}{2(r^2+R^2)^{\frac{3}{2}}}(1)

\mu_0 is the permeability of free space, I is the flowing current  through the ring, R is the ring's radius and r is the distance to the center of the ring.

The flowing current  through the ring is defined as the ring's charge divided into the time taken by the charge to complete one revolution, that is, the period T=\frac{2\pi}{\omega}. So, we have:

I=\frac{q}{T}\\I=\frac{q}{\frac{2\pi}{\omega}}\\\\I=\frac{\omega q}{2\pi}\\I=\frac{18\frac{rad}{s}(10*10^{-6}C)}{2\pi}\\I=2.87*10^{-5}A

Now, replacing in (1):

B=\frac{(4\pi*10^{-7}\frac{T\cdot m}{A})(2.87*10^{-5}A)(0.115m)^2}{2((0.05m)^2+(0.115m)^2)^{\frac{3}{2}}}\\B=1.21*10^{-10}T

6 0
4 years ago
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