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Aleks04 [339]
2 years ago
14

A car drives straight down toward the bottom of a valley and up the other side on a road whose bottom has a radius of curvature

of 115m. At the very bottom, the normal force on the driver is twice his weight. At what speed was the car traveling?
Physics
1 answer:
mina [271]2 years ago
6 0

Answer:33.58794 m/s

Explanation : fCenrtipetal force = mv2/r

m = Mass of car

r = Radius of curvature = 115 m

g = Acceleration due to gravity = 9.81 m/s²

The normal force is given by

N=Fc+mg

At the bottom N = 2N

2mg=fc+mg

⇒2mg=mv2

The car was traveling at the speed of 33.58794 m/s

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Answer:

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Explanation:

First, we can use the following sketch for an easy understanding, in the attached image we can see the two pressure gauges the one with mercury to the right and the other one with oil to left. We have all the information needed in the mercury pressure gauge, so we can determine the pressure inside the vessel because the fluid is a gas it will have the same pressure distributed inside the vessel (P1).

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3 years ago
27. The traffic officer issued violation tickets to traffic
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Answer:

27: 85

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Explanation:

27:68=80

?=100 hence (68×100)÷80

=85

28:<em>1</em><em>8</em><em>/</em><em>2</em><em>4</em><em>×</em><em> </em><em>1</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>7</em><em>5</em><em>%</em>

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Answer:

a=0.555m/s^2

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