The moment of inertia of a uniform solid sphere is equal to 0.448
.
<u>Given the following data:</u>
Mass of sphere = 7 kg.
Radius of sphere = 0.4 meter.
<h3>How to calculate moment of inertia.</h3>
Mathematically, the moment of inertia of a solid sphere is given by this formula:

<u>Where:</u>
- I is the moment of inertia.
Substituting the given parameters into the formula, we have;

I = 0.448
.
Read more on inertia here: brainly.com/question/3406242
Answer:
Explanation:
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Answer:
The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N
Explanation:
The details of the given masses having gravitational attractive force between them are;
m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m
The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;

Where;
F = The gravitational force between m₁ and m₂
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
r₂ = 0.1 m + 0.15 m = 0.25 m
Therefore, we have;

The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N