so as this ant moves
5 cm every second you multiply 5 by 120 (60 per minute as there are 60 seconds in a minute)
this is 600 cm
or
6 meters
Answer:

Explanation:
<u>Given:</u>
Force = f = 60 N
Mass = m = 12 kg
<u>Required:</u>
Acceleration = a = ?
<u>Formula:</u>
F = ma
<u>Solution:</u>
Rearranging formula
a = F / m
a = 60 / 12
a = 5 ms⁻²
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>
Answer:
time spent = 0.2276
Explanation:
given data
distance = 135 mi
usual speed = 65 mph
today speed = 73 mph
solution
we get here time that is express as
time =
...................1
usual time =
= 2.0769 h
today time =
= 1.8493 h
so we get here time spent as
time spent = 2.0769 h - 1.8493 h
time spent = 0.2276
Answer:
v = 7934.2 m/s
Explanation:
Here the total energy of the Asteroid and the Earth system will remains conserved
So we will have

now we know that





now from above formula

now we have

now plug in all data


Answer:
Acceleration is the rate of change of velocity. Usually, acceleration means the speed is changing, but not always. When an object moves in a circular path at a constant speed, it is still accelerating, because the direction of its velocity is changing. Comment on robshowsides's post “Speed is the magnitude of velocity.
Explanation:
hope it helped tee hee