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Fynjy0 [20]
2 years ago
10

Given cos theta = √3/3 and sin theta < 0. What is the value of sin theta? ​

Mathematics
1 answer:
kirill115 [55]2 years ago
8 0

The value of the sin theta will be equal to Sin\theta =\sqrt{\dfrac{2}{3}}

<h3>What is trigonometry?</h3>

The branch of mathematics sets up a relationship between the sides and the angles of the right-angle triangle termed trigonometry.

Given that:-

  • Cos\theta = √3/3
  • Sin\theta <0

The value of Sin will be calculated as:-

Sin^2\theta +Cos^2\theta = 1\\\\Sin^2\theta + \dfrac{\sqrt{3}}{2}=1\\\\Sin^2\theta  = 1 -\dfrac{1}{3}\\\\Sin\theta = \sqrt{\dfrac{2}{3}}

We can see that the value of sin is less than zero therefore

To know more about Trigonometry follow

brainly.com/question/24349828

#SPJ1

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