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Arada [10]
3 years ago
7

Calculate the percent activity of the radioactive isotope strontium-89 remaining after 5 half-lives.

Chemistry
1 answer:
maria [59]3 years ago
5 0
The answer to this question would be: 3.125%

Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
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Explanation:

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2 years ago
Which of the following equations of CH4 + Cl2
mylen [45]

Balanced equation : C. CH₄ + 4Cl₂⇒  CCl₄+ 4HCl

<h3>Further explanation  </h3>

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:  

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.  

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product  

3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

Reaction

CH₄ + Cl₂⇒  CCl₄+ HCl

  • Give coefficient :

aCH₄ + bCl₂⇒  CCl₄+ cHCl

  • Make equation :

C, left=a, right=1⇒a=1

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The equation becomes :

CH₄ + 4Cl₂⇒  CCl₄+ 4HCl

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3 years ago
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Read 2 more answers
Rainly
Pani-rosa [81]

Answer:

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