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aliina [53]
2 years ago
9

With the aid of a power reducing formula, 14sin² acos² a = ?

Mathematics
1 answer:
Shtirlitz [24]2 years ago
6 0

The reduced form of the trig expression is 7/2sin²2a

<h3>Trigonometry identity</h3>

Trigonometry identities are written in terms of sine, cosine and tangent. Given the trigonometry identity

14sin² acos² a

Since sin(a)cos(a) = sin2a/2, hence

14sin²acos²a = 14[sin(a)cos(a)]²

14sin²acos²a = 14(sin2a/2)²

14sin²acos²a = 14/4(sin²2a)

14sin²acos²a = 7/2sin²2a

Hence the reduced form of the trig expression is 7/2sin²2a

Learn more on trigonometry expression here: brainly.com/question/27904371

#SPJ1

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What is the result of 4/ 1/2
Gemiola [76]

\bf \cfrac{~~4~~}{\frac{1}{2}}\implies \cfrac{~~\frac{4}{1}~~}{\frac{1}{2}}\implies \cfrac{4}{1}\cdot \cfrac{2}{1}\implies 8

7 0
4 years ago
Rewrite without parenthesis and simplify (y+6)^2
GarryVolchara [31]
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4 0
3 years ago
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Find the measure of the indicated angle to the nearest degree
shutvik [7]

\cos \theta =\dfrac{18}{23}\\\\\implies \theta = \cos^{-1}\left(\dfrac{18}{23} \right)=38.5^{\circ} \approx 39^{\circ}

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=f%28n%29%3D3%5En" id="TexFormula1" title="f(n)=3^n" alt="f(n)=3^n" align="absmiddle" class="la
andrezito [222]

Answer:

24(f(n))

Step-by-step explanation:

f(n+3) = 3^{n+3}\\f(n+1) = 3^{n+1}

so

f(n+3) - f(n+1) = 3^{n+3} - 3^{n+1}

= 27(3^n) - 3(3^n)

= 24(3^n)

= 24(f(n))

hope this helped! :)

4 0
2 years ago
A club began with 3 members. Each month, each member brought one new member. Which function can be used to determine the number
erastova [34]

In x th month, members =  3^{2x}. Option D.

Step-by-step explanation:

Given,

Initially number of members = 3

Every month each member brought 1 new member.

To find the number of members after x months.

<u>Solution:</u>

In 1st month, members = 3

In 2nd month, members = 3×3 = 9 = 3²

In 3rd month, members = 9×9 = 81 = 3^{4}

In 4th month, members = 81×81 = 81 = 6561 = 3^{8}

Hence,

In x th month, members =  3^{2x}

3 0
4 years ago
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