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aliina [53]
2 years ago
9

With the aid of a power reducing formula, 14sin² acos² a = ?

Mathematics
1 answer:
Shtirlitz [24]2 years ago
6 0

The reduced form of the trig expression is 7/2sin²2a

<h3>Trigonometry identity</h3>

Trigonometry identities are written in terms of sine, cosine and tangent. Given the trigonometry identity

14sin² acos² a

Since sin(a)cos(a) = sin2a/2, hence

14sin²acos²a = 14[sin(a)cos(a)]²

14sin²acos²a = 14(sin2a/2)²

14sin²acos²a = 14/4(sin²2a)

14sin²acos²a = 7/2sin²2a

Hence the reduced form of the trig expression is 7/2sin²2a

Learn more on trigonometry expression here: brainly.com/question/27904371

#SPJ1

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