Question

With the aid of a power reducing formula, 14sin² acos² a = ?

Answer 1

The reduced form of the trig expression is 7/2sin²2a

Trigonometry identity

Trigonometry identities are written in terms of sine, cosine and tangent. Given the trigonometry identity

14sin² acos² a

Since sin(a)cos(a) = sin2a/2, hence

14sin²acos²a = 14[sin(a)cos(a)]²

14sin²acos²a = 14(sin2a/2)²

14sin²acos²a = 14/4(sin²2a)

14sin²acos²a = 7/2sin²2a

Hence the reduced form of the trig expression is 7/2sin²2a

Learn more on trigonometry expression here: brainly.com/question/27904371

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