1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lana71 [14]
2 years ago
11

The box resting on the inclined plane above has a mass of 20kg. The incline sits at a 30o angle. Find the friction force between

the box and the incline if the box does not slide down the incline.
Physics
2 answers:
tekilochka [14]2 years ago
3 0

The friction force between the box and the incline if the box does not slide down the incline will be 0.577

The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction. There are several kinds of friction: Two solid surfaces in touch are opposed to one another's relative lateral motion by dry friction.

Given the box resting on the inclined plane above has a mass of 20kg and the The incline sits at a 30 degree angle

We have to find the friction force between the box and the incline if the box does not slide down the incline

Since the frictional force F₁ must equal or exceed gravitational force F₂ down the incline:

F₁ = F₂

μmgcosΘ = mgsinΘ

μ = (mgsinΘ)/(mgcosΘ)

μ = tanΘ

μ = 0.577

Hence the friction force between the box and the incline if the box does not slide down the incline will be 0.577

Learn more about friction force here:

brainly.com/question/24386803

#SPJ4

Juliette [100K]2 years ago
3 0

:The resistance created by the box's friction with the incline The slope will be 0.577 if the box doesn't descend.

Friction is the force that prevents solid surfaces, fluid layers, and material constituents from sliding past one another. Different types of friction exist. Dry friction opposes the relative lateral motion of two touching solid surfaces.

Given that the 20-kg box lying on the inclined plane above and the incline's 30 degree inclination

If the box does not slide down the incline, we must determine the friction force between them.

Given that the gravitational force F2 down the gradient must be equal to or greater than the frictional force F1,

F₁ = F₂

If mgcosx = mgsinx

equals (mgsinx)/(mgcosx)

μ = tanx

μ = 0.577

Therefore, if the box does not slide down the incline, the friction force between the box and the incline will be 0.577.

Here is further information on friction force.

brainly.com/question/1714663

#SPJ4

You might be interested in
An attractive force of 7.2 N occurs between two point charges that are 0.10 m apart. If one charge is -4.0 µC, what is the other
Umnica [9.8K]
The answer is c. +2.0 µC

To calculate this, we will use Coulomb's Law:

F = k*Q1*Q2/r²

where F is force, k is constant, Q is a charge, r is a distance between charges.

k = 9.0 × 10⁹  N*m/C²


It is given:

F = 7.2 N

d = 0.1 m =  10⁻¹ m

Q1 = -4.0 µC = 4 * 1.0 × 10⁻⁶ = 4.0 × 10⁻⁶

Q2 = ?


Thus, let's replace this in the formula for the force:

7.2 = 9.0 × 10⁹ * 4.0 × 10⁻⁶ * Q2/(10⁻¹)²

7.2 = 9 * 4 * 10⁹⁻⁶ * Q2/10⁻¹°²

7.2 = 36 × 10³ * Q2 / 10⁻²

Multiply both sides of the equation by 10⁻²:

7.2 × 10⁻² = 36 × 10³ * Q2

⇒ Q2 = 7.2 × 10⁻² / 36 × 10³ = 7.2/36 × 10⁻²⁻³ = 0.2 × 10⁻⁵ = 2 × 10⁻⁶ 


Since µC = 1.0 × 10^-6:

Q2 = 2 * 1.0 × 10^-6 = 2 µC

5 0
3 years ago
Two bodies, one hot and the other cold kept in vacuum.what will happen to the tempreture of bodies after some time.
Dovator [93]
Hot body will lose heat from it, and that heat will goes out from it through radiation, so it's temperature will decrease after some time.

In same manner, cold body will take the heat, and it's temperature will increase

Hope this helps!
7 0
3 years ago
A stone is catapulted at time t = 0, with an initial velocity of magnitude 19.9 m/s and at an angle of 39.9° above the horizonta
larisa [96]

Answer:

Part a)

x = 15.76 m

Part b)

y = 7.94 m

Part c)

x = 26.16 m

Part d)

y = 7.49 m

Part e)

x = 83.23 m

Part f)

y = -75.6 m

Explanation:

As we know that catapult is projected with speed 19.9 m/s

so here we have

v_x = 19.9 cos39.9

v_x = 15.3 m/s

similarly we have

v_y = 19.9 sin39.9

v_y = 12.76 m/s

Part a)

Horizontal displacement in 1.03 s

x = v_x t

x = (15.3)(1.03)

x = 15.76 m

Part b)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(1.03) - 4.9(1.03)^2

y = 7.94 m

Part c)

Horizontal displacement in 1.71 s

x = v_x t

x = (15.3)(1.71)

x = 26.16 m

Part d)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(1.71) - 4.9(1.71)^2

y = 7.49 m

Part e)

Horizontal displacement in 5.44 s

x = v_x t

x = (15.3)(5.44)

x = 83.23 m

Part f)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(5.44) - 4.9(5.44)^2

y = -75.6 m

6 0
3 years ago
What can reduce a machines efficiency
algol [13]

Answer:

its power.

Explanation:

6 0
3 years ago
Read 2 more answers
In what layer of earth does the temperature rise the fastest <br><br> This is for earth science!!!
CaHeK987 [17]

Answer:

thermosphere

Explanation:

i think

6 0
3 years ago
Other questions:
  • PULLEYS UNIT: HELP!
    7·1 answer
  • How many degrees in fahrenheit is 6.75 degrees celsius?
    12·1 answer
  • In the gene TATTCATTGTTA—TGATTT—ATTCG, CATTGTTA encodes for pepsin, a digestive enzyme. The rest of the sequence doesn’t code fo
    13·1 answer
  • a child sleds down a steep snow-covered hill with an acceleration of 3.94 m/s^2. if her initial speed is 0.0m/s and her final sp
    15·1 answer
  • When sugar is poured from the box into the sugar bowl, the rubbing of sugar grains creates a static electric charge that repels
    14·1 answer
  • Police lieutenants, examining the scene of an accident involving two cars, measure the skid marks of one of the cars, which near
    10·1 answer
  • PLEASE ASAP ILL GIVE BRAINLIEST.
    13·1 answer
  • You are in a car and go around a corner very fast. What happens to you?
    14·1 answer
  • Hi people see bye 18 45 36
    10·1 answer
  • A propane tank is filled with a mixture of liquid and vapor propane. Can the contents of this tank be considered a pure substanc
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!