Answer:
The frequency of the tuning is 1.065 kHz
Explanation:
Given that,
Length of tube = 40 cm
We need to calculate the difference between each of the lengths
Using formula for length
![\Delta L=L_{2}-L_{1}](https://tex.z-dn.net/?f=%5CDelta%20L%3DL_%7B2%7D-L_%7B1%7D)
![\Delta L=74.7-58.6](https://tex.z-dn.net/?f=%5CDelta%20L%3D74.7-58.6)
![\Delta L=16.1\ m](https://tex.z-dn.net/?f=%5CDelta%20L%3D16.1%5C%20m)
For an open-open tube,
We need to calculate the fundamental wavelength
Using formula of wavelength
![\lambda=2\Delta L](https://tex.z-dn.net/?f=%5Clambda%3D2%5CDelta%20L)
Put the value into the formula
![\lambda=2\times16.1](https://tex.z-dn.net/?f=%5Clambda%3D2%5Ctimes16.1)
![\lambda=32.2\ cm](https://tex.z-dn.net/?f=%5Clambda%3D32.2%5C%20cm)
We need to calculate the frequency of the tuning
Using formula of frequency
![f=\dfrac{v}{\lambda}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7Bv%7D%7B%5Clambda%7D)
Put the value into the formula
![f=\dfrac{343}{32.2\times10^{-2}}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B343%7D%7B32.2%5Ctimes10%5E%7B-2%7D%7D)
![f=1065.2\ Hz](https://tex.z-dn.net/?f=f%3D1065.2%5C%20Hz)
![f=1.065\ kHz](https://tex.z-dn.net/?f=f%3D1.065%5C%20kHz)
Hence, The frequency of the tuning is 1.065 kHz
Answer:
v = 0.059 m/s
Explanation:
To find the final speed of Olaf and the ball you use the conservation momentum law. The momentum of Olaf and the ball before catches the ball is the same of the momentum of Olaf and the ball after. Then, you have:
(1)
m: mass of the ball = 0.400kg
M: mass of Olaf = 75.0 kg
v1i: initial velocity of the ball = 11.3m/s
v2i: initial velocity of Olaf = 0m/s
v: final velocity of Olaf and the ball
You solve the equation (1) for v and replace the values of all variables:
![v=\frac{mv_{1i}}{m+M}=\frac{(0.400kg)(11.3m/s)}{0.400kg+75.0kg}=0.059\frac{m}{s}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bmv_%7B1i%7D%7D%7Bm%2BM%7D%3D%5Cfrac%7B%280.400kg%29%2811.3m%2Fs%29%7D%7B0.400kg%2B75.0kg%7D%3D0.059%5Cfrac%7Bm%7D%7Bs%7D)
Hence, after Olaf catches the ball, the velocity of Olaf and the ball is 0.059m/s
The potential energy of an object is defined by the equation: PE = mgh, where m = the mass of the object, g = the gravitational acceleration and h = the object's height above the ground.
Mechanical waves transfer energy by inducing vibrations in the propagation medium.