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sleet_krkn [62]
2 years ago
7

In this experiment you used an excess of the BaCl2 solution. How would your results be affected if you did not use an excess of

the BaCl2 solution? Would this error cause your calculation of the mass percent of sulfate in the unknown to be too high or too low? Explain.
Chemistry
1 answer:
Igoryamba2 years ago
3 0

if we did not use an excess of the BaCl2 solution it would decrease the mass percentage of sulfate in the unknown sample.

The net precipitation equation would be.

Ba2+(aq) + SO42-(aq)  → BaSO4(s)

If BaCl2 (Ba2+) is not taken in excess then the precipitation would not be completed as some of the sulfate ions would still be remaining in the solution. This would decrease the mass percentage of sulfate in the unknown sample.

If some tiny pieces of filter paper still remained mixed with the precipitate(BaSO4) then the mass of sulfate would increase and it gives a high mass percentage of the sulfate.

mass percentage of sulfate = (mass of sulfate/mass of sample)*100

Learn more about precipitation here brainly.com/question/14675507

#SPJ4

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In which layer of the ocean do surface currents flow?
Marat540 [252]

Answer:

ooh sorry, but will this help you now:

Ocean dynamics define and describe the motion of water within the oceans. Ocean temperature and motion fields can be separated into three distinct layers: mixed (surface) layer, upper ocean (above the thermocline), and deep ocean. Ocean currents are measured in sverdrup (sv), where 1 sv is equivalent to a volume flow rate of 1,000,000 m (35,000,000 cu ft) per second.

Surface currents, which make up only 8% of all water in the ocean, are generally restricted to the upper 4…

Explanation:

Hope this helps :)

8 0
3 years ago
a compound has a molar mass of 129 g/mol if its empirical formula is C2H5N then what is the molecular formula
Elena-2011 [213]

Given :

A compound has a molar mass of 129 g/mol .

Empirical formula of compound is C₂H₅N .

To Find :

The molecular formula of the compound.

Solution :

Empirical mass of compound :

M_e = ( 2 \times 12 ) + ( 5 \times 1 ) + (  1  \times 14 )\\\\M_e = 43\ gram/mol

Now, n-factor is :

n = \dfrac{M}{M_e}\\\\n = \dfrac{129}{43}\\\\n = 3

Multiplying each atom in the formula by 3 , we get :

Molecular Formula, C₆H₁₅N₃

3 0
3 years ago
What is one energy transformation that is taking place in the photo?
Galina-37 [17]

I'm guessing the photo means photosynthesis. In that case, it is solar energy to chemical energy. Radiant energy and solar energy is kind of the same thing, so 4th answer.

4 0
2 years ago
Read 2 more answers
Identify what kind of ligand (weak or strong), what kind of wavelength (long or short), what kind of spin (high spin or low spin
anzhelika [568]

To find - Identify what kind of ligand (weak or strong), what kind

              of wavelength (long or short), what kind of spin (high spin or

              low spin) and whether it is paramagnetic or diamagnetic for

              the following complexes.

              1. [Mn(CN)6]4-

              2. [Fe(OH)(H2O)5]2

              3. [CrCl4Br2]3-

Step - by - Step Explanation -

1.

[Mn(CN)⁶]⁴⁻ :

Ligand - Strong

Wavelength - Short

Spin - Low spin

Number of unpaired electrons = 1 ∴ paramagnetic.

2.

[Fe(OH)(H₂O)₅]²⁺ :

Ligand - Weak ( both OH⁻ and H₂O )

Wavelength - Long

Spin - High spin

Number of unpaired electrons = 5 ∴ paramagnetic.

3.

[CrCl₄Br₂]³⁻ :

Ligand - Weak ( both Br⁻ and Cl⁻ )

Wavelength - Long

Spin - High spin

Number of unpaired electrons = 3 ∴ paramagnetic.

7 0
2 years ago
NaOH(aq) is transferred into a test tube. CaCl2(aq) is added to the tube. What is the formula for the precipitate (if any) that
Ilya [14]

Answer:

2NaOH (aq) + CaCl2 (aq) -> 2NaCl(aq) + Ca(OH)2(s)

Formula of precipitate: Ca(OH)2 <em>(s)</em>

Explanation:

First, we do the double replacement reaction to determine our chemical equation between the reactants and products. Once we have our products, with a solubility chart (I added one below) we can determine which of the products is soluble or insoluble.

In this case NaCl is soluble or aqueous (meaning it can dissolve in water) and Ca(OH)2 is insoluble (meaning that when the reactions takes place, these two will form a solid/precipitate)

6 0
2 years ago
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