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sleet_krkn [62]
2 years ago
7

In this experiment you used an excess of the BaCl2 solution. How would your results be affected if you did not use an excess of

the BaCl2 solution? Would this error cause your calculation of the mass percent of sulfate in the unknown to be too high or too low? Explain.
Chemistry
1 answer:
Igoryamba2 years ago
3 0

if we did not use an excess of the BaCl2 solution it would decrease the mass percentage of sulfate in the unknown sample.

The net precipitation equation would be.

Ba2+(aq) + SO42-(aq)  → BaSO4(s)

If BaCl2 (Ba2+) is not taken in excess then the precipitation would not be completed as some of the sulfate ions would still be remaining in the solution. This would decrease the mass percentage of sulfate in the unknown sample.

If some tiny pieces of filter paper still remained mixed with the precipitate(BaSO4) then the mass of sulfate would increase and it gives a high mass percentage of the sulfate.

mass percentage of sulfate = (mass of sulfate/mass of sample)*100

Learn more about precipitation here brainly.com/question/14675507

#SPJ4

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Adjust your day-to-day behaviors.

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3 0
3 years ago
Hydrogen is a gas at a room temperature, but it is found with the alkali metals in group 1 (1A) on the periodic table. Which is
bearhunter [10]
Hydrogen is grouped with the alkali metals because they are grouped based on their properties and behavior, and like the other elements in Group 1 (1A), it only has one valence.
5 0
3 years ago
Calculate the volume of a box with the following dimensions: length=8 cm
wel

Answer:  240 cm³

Explanation:

Volume of the box = l × w × h

                               = (8 cm × 6 cm × 5 cm)

                               = 240 cm³

8 0
2 years ago
A solution of h2so4(aq) with a molal concentration of 2.24 m has a density of 1.135 g/ml. what is the molar concentration of thi
OLga [1]
This problem is simply converting the concentration from molality to molarity. Molality has units of mol solute/kg solvent, while molarity has units of mol solute/L solution.

2.24 mol H2SO4/kg H2O * (0.25806 kg H2SO4/mol H2SO4) = 0.578 kg H2SO4/kg H2O

That means the solution weighs a total of 1 kg + 0.578 kg = 1.578 kg. Then, convert it to liters using the density data:

1.578 kg * (1000g / 1kg) * (1 mL/1.135 g) = 1390 mL or 1.39 L.

Hence, the molarity is

2.24/1.39 = 1.61 M
7 0
3 years ago
In a water molecule (H2O), the oxygen atom has two unshared pairs of electrons and two bonding pairs of electrons. How do the un
vladimir1956 [14]

Answer:

They reduce the bond angle to be slightly lower than the tetrahedral bond angle, approximately 104.45 degrees.

Explanation:

The unshared pair of electrons or lone pair electrons in order to have the minimum repulsion possible with each other pushes the other bonding pairs closer together making the bond angle smaller or bent.

The bond angle is slightly lower than the tetrahedral bond angle of 108 degrees, leaving the water molecule with a bent molecular geometry.

4 0
3 years ago
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