Answer:
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<u>Answer:</u> The expression of
for calcium fluoride is ![K_{sp}=[Ca^{2+}][2F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5B2F%5E-%5D%5E2)
<u>Explanation:</u>
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.
The given chemical equation follows:

1 mole of calcium fluoride produces 1 mole of calcium ions and 2 moles of fluorine ions.
The expression of
for above equation follows:
![K_{sp}=[Ca^{2+}][2F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5B2F%5E-%5D%5E2)
Hence, the expression of
for calcium fluoride is ![K_{sp}=[Ca^{2+}][2F^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5B2F%5E-%5D%5E2)