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deff fn [24]
2 years ago
5

The atomic mass unit is presently based on assigning an exact integral mass (in amu) to an isotope of an hydrogen oxygen sodium

carbon helium
a. hydrogen

b. oxygen

c. sodium

d. carbon

e. helium
Chemistry
2 answers:
Stels [109]2 years ago
7 0

Carbon is the reference taken to assign the atomic mass unit

  • One twelfth of the mass of unbound carbon-12 is taken as 1amu
  • The unit for the atomic mass constant is Dalton (Da)
  • This unit is standard when doing calculations in chemistry and physics
  • 1amu = 1.6605x10⁻¹⁹g
  • This was also derived from the law of definite proportions
  • This standard has been set by the International Union of Pure and Applied Chemistry (IUPAC)
  • The IUPAC is responsible for assigning various standards such as the nomenclature of various compounds, and updating the periodic table of elements.
  • According to the IUPAC carbon is the reference taken to assign the atomic mass unit

Learn more about atomic mass units here:

brainly.com/question/338808

#SPJ10

GrogVix [38]2 years ago
4 0

Answer: a. hydrogen

This is a fact.

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What is Gibbs free energy
Alenkinab [10]

Answer:

The minimum amount of energy needed the the cell to perform various cellular,biochemical and physiological activities is known is Gibbs free energy.

Explanation:

The change in gibbs free energy of is very much important to determine whether a given reaction is spontaneous,non spontaneous  or equilibrium.

 1 If gibbs free energy change of a reaction is negative then the reaction is spontaneous.

2  If the free energy change is 0 then the reaction is in equilibrium stage.

3  If free energy change is positive then the reaction is non spontaneous.

4 0
3 years ago
A voltaic cell utilizes the following reaction: 4Fe2+(aq)+O2(g)+4H+(aq)→4Fe3+(aq)+2H2O(l). What is the emf of this cell under st
Leviafan [203]

Answer:

0.46 V

Explanation:

The emf for the cell is given by:

Eº cell = Eº oxidation + Eº reduction

From the  given balanced chemical equation, we can deduce that Fe²⁺ has been oxidized to Fe³⁺, and O reduced  from 0 to negative 2, according to the half cell reactions:

4Fe²⁺  ⇒ Fe³⁺ + 4e⁻           oxidation

O₂ + 4H⁺ + 4 e⁻ ⇒ 2 H₂O   reduction

From reference tables for the standard reduction potential, we get

Eº red Fe³⁺ / Fe²⁺   Eºred = 0.77 V  

Eº red O₂ / H₂O      Eºred = 1.23 V

Now all we need to do is change the sign of Eº reduction for the species being oxidized ( Fe²⁺ ) and add it to Eº reduction  O₂:

Eº cell =   Eº oxidation + Eº reduction = - (0.77 V ) + 1.23 V = 0.46 V

5 0
4 years ago
30 POINTS!!!<br> NEED ASAL
nata0808 [166]

Answer:

ITS THE LAST ONE AND THE SECOND ONE

Explanation:

4 0
3 years ago
Enter your answer in the box provided. How many grams of helium must be added to a balloon containing 6.24 g helium gas to doubl
Archy [21]

Answer : The mass of helium gas added must be 12.48 grams.

Explanation : Given,

Mass of helium (He) gas = 6.24 g

Molar mass of helium = 4 g/mole

First we have to calculate the moles of helium gas.

\text{Moles of }He=\frac{\text{Mass of }He}{\text{Molar mass of }He}=\frac{6.24g}{4g/mole}=1.56moles

Now we have to calculate the moles of helium gas at doubled volume.

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

V\propto n

or,

\frac{V_1}{V_2}=\frac{n_1}{n_2}

where,

V_1 = initial volume of gas  = V

V_2 = final volume of gas = 2V

n_1 = initial moles of gas  = 1.56 mole

n_2 = final moles of gas  = ?

Now we put all the given values in this formula, we get

\frac{V}{2V}=\frac{1.56mole}{n_2}

n_2=3.12mole

Now we have to calculate the mass of helium gas at doubled volume.

\text{Mass of }He=\text{Moles of }He\times \text{Molar mass of }He

\text{Mass of }He=3.12mole\times 4g/mole=12.48g

Therefore, the mass of helium gas added must be 12.48 grams.

4 0
3 years ago
What is the gravitational potential energy of a 5 kg object that is 150
marusya05 [52]

Explanation:

Gravitational potential energy

= mgh

= (5kg)(9.81N/kg)(150m)

= 7357.5J.

5 0
3 years ago
Read 2 more answers
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