4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.
<h3>What are Noble Gases ?</h3>
The noble gases are helium, argon, krypton, xenon, and radon, in order of their mass.
They are called noble gases because they are so majestic that they do not react with anything in general.
The work done can be calculated by the formula
Q=n Cp ΔT
Cp= ( 1+ f/2)R
R= 8.3144598 J. mol-1.
Cp = (1+3/2) * 8.314
Cp = 5*8.314/2
Q= 2 * 5 *8.314 *100/2
Q = 4157 J
Therefore 4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.
To know more about Noble Gas
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The number of protons in the nucleus for that element
Friction .......................................................................................
Answer:
Explanation:
a )
energy produced per second = 500 J
Heat produced = 500 x .8 = 400 J per second.
If m be the mass of water evaporated per unit hour
m x latent heat = 400 x 60 x 60
= m x 2.42 x 10⁶ = 1.44 x 10⁶
m = .595 kg per hour
b )
volume of water = 595 mL
bottles = 595 / 750
.8 or 4/5 of bottle. per hour.