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Nitella [24]
3 years ago
6

Prepare 15 mg/dl working standard solution from a stock solution of 20 mg/dl. State the volume of diluent and dilution.

Chemistry
1 answer:
Anastasy [175]3 years ago
4 0

Preparing 15 mg/gl working standard solution from a 20 mg/dl stock solution will require the application of the dilution principle.

Recalling the principle:

initial volume x initial molarity = final volume x final molarity

Since we were not given any volume to work with, we can as well just take an arbitrary volume to be prepared. Let's assume that the stock solution is 10 mL and we want to prepare 15 mg/gl from it:

Applying the dilution principle:

10 x 20 = final volume x 15

final volume = 200/15

                       = 13.33 mL

This means that in order to prepare 13.33 mL, 15 mg/l working standard solution from 10 ml, 20 mg/dl stock solution, 3.33 mL of the diluent must be added to the stock solution.

More on dilution principle can be found here: brainly.com/question/11493179

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180 g of aspirin contains 1 mole of aspirin molecules i.e, 6.023 X 10²³ number of aspirin molecules.  So, three alka-seltzer tablet that is 0.972 g of aspirin contains (0.972 X 6.023 X 10²³)/180 =3.25 X 10²¹ number of aspirin molecules.

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What is the minimum mass of ice at 0.0 C that must be added to 1.00 kg of water to cool the water from 28.0 C to 12.0 C? (Hea
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For example, methane is tetrahedral as four hydrogen atoms are bonded to carbon and there is no lone pair of electrons present on C. Here, the sum of bonding groups and lone pairs is 4.

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