Answer:
D. 0.543kg of copper metal is produced from 0.680kg of copper 1 sulphide.
Explanation:
First write the equation for the reaction:
Cu2S + O2 ------> 2Cu + SO2
Determine the mole ratio of the two substances:
I mole of Cu2O forms 2 moles of Copper metal
The number of moles of copper 1 sulphide used is;
n = mass of Cu2S / molar mass of Cu2S
Mass = 0.680kg = 680g
Molar mass = 159.16g/mol
n = 680g / 159.16g/mol
n = 4.272moles
Determine the number of mole of copper:
Number of moles of copper metal produced from 4.272moles of copper 1 sulphide is therefore:
n of copper = 2 * 4.272 Moles
n = 8.544moles.
Determine the mass copper:
The mass of copper metal produced is therefore = number of moles of copper * molar mass of copper
mass = 8.544 moles * 63.55g/mol
mass = 542.97grams
Mass = 0.543kg
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<span>18.01528 g/mol is the molar mass of H2O</span>
Answer:
C2H4O2 + 2O2 —> 2CO2 + 2H20
The coefficients are 1, 2, 2, 2
Explanation:
C2H4O2 + O2 —> CO2 + H20
To balance the above, do the following
Since there are 2 carbon on the left, put 2 in front of CO2, we have
C2H4O2 + O2 —> 2CO2 + H20
We have 4 hydrogen on the left, to balance it put 2 in front of H2O i.e
C2H4O2 + O2 —> 2CO2 + 2H20
Now, we have a total of 6 oxygen on the right side. To balance it, put 2 in front of O2:
C2H4O2 + 2O2 —> 2CO2 + 2H20
The coefficients are 1, 2, 2, 2
We will use Arrehenius equation
lnK = lnA -( Ea / RT)
R = gas constant = 8.314 J / mol K
T = temperature = 25 C = 298 K
A = frequency factor
ln A = ln (1.5×10 ^11) = 25.73
Ea = activation energy = 56.9 kj/mol = 56900 J / mol
lnK = 25.73 - (56900 / 8.314 X 298) = 2.76
Taking antilog
K = 15.8