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antoniya [11.8K]
2 years ago
11

What is a neutral atom of nitrogen-14

Chemistry
1 answer:
salantis [7]2 years ago
5 0

Answer:

You know that nitrogen-14 has 7 protons in the nucleus because it is an isotope of nitrogen, which has an atomic number equal to 7 . Because nitrogen-14 is a neutral atom, the number of protons it has in its nucleus must be equal to the number of electrons that surround its nucleus.

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What is the oxidation number of P in PF6^-
Hitman42 [59]
<span>F can only have oxidation number of -1
The overall compound has an oxidation number of -1
You have 6 Fs, so 6(-1) = -6
charge from F
 X = oxidation number of P
 x + (-6) = -1
solve for
x = +5</span>
5 0
3 years ago
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Compare (a) the number of drops and (b) the length of time, in minutes, required to deliver 50 mL of intravenous solutions when
Marina CMI [18]

Explanation:

Volume of intravenous solution to be delivered = 50 mL

1) Rate of drops per milliliter of the solution = r = 60 drops/mL

Number of drops delivered :

60 drops/mL\times 50 mL = 3000 drops

Time required to deliver 3000 drops = t

Rate of drop solution with respect to time = R = 1 drop/second

\frac{3000 drop}{t}=1 drop/s

t = 3000 seconds = 50 minutes (1 min = 60 seconds)

Number of drops delivered 3000.

50 minutes are required to deliver 50 mL of intravenous solutions.

2) Rate of drops per milliliter of the solution = r = 15 drops/mL

Number of drops delivered :

15 drops/mL\times 50 mL = 750 drops

Time required to deliver 750 drops = t

Rate of drop solution with respect to time = R = 1 drop/second

\frac{750 drop}{t}=1 drop/s

t = 750 seconds = 12.5 minutes (1 min = 60 seconds)

Number of drops delivered 750 .

12.5 minutes are required to deliver 50 mL of intravenous solutions.

7 0
4 years ago
What's the scientific notation for 0.4600
Veseljchak [2.6K]
4.6 x 10 to the -1 power.
5 0
3 years ago
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Chemistry !!!!! HELP !!!!!!!!
lyudmila [28]
Ill try to help you find the answer
3 0
3 years ago
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Solving stoichiometry problems that involve mass Now that you know the molar masses of the relevant compounds, you are ready to
Shalnov [3]

14.85 g of water

Explanation:

Calculate the mass of water produced when 9.56 g of butane reacts with excess oxygen.

Here we have the full oxidation of butane (C₄H₁₀) which produce carbon dioxide and water.

C₄H₁₀ + (13/2) O₂ → 4 CO₂ + 5 H₂O

number of moles = mass / molecular weight

number of moles of butane = 9.56 / 58 = 0.165 moles

Now, taking in account the chemical reaction, we devise the following reasoning:

if         1 mole of butane produces 5 moles of water

then    0.165 moles of butane produces X moles of water

X = (0.165 × 5) / 1 = 0.825 moles of water

mass = number of moles × molecular weight

mass of water = 0.825 × 18 = 14.85 g

Learn more about:

oxidation of hydrocarbons

brainly.com/question/10195442

brainly.com/question/7295137

#learnwithBrainly

4 0
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