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2 years ago

What is the oxidation number of P in PF6^-

Chemistry

2 answers:

ioda2 years ago

7 0

Answer:

The answer is: +5.

Explanation:

PF6 ^ - >>> P (+5) F (-1) 6-

Element: P F

Oxidation Number: +5 -1

The answer is: +5.

Hitman42 [59]2 years ago

5 0

F can only have oxidation number of -1
The overall compound has an oxidation number of -1
You have 6 Fs, so 6(-1) = -6
charge from F
X = oxidation number of P
x + (-6) = -1
solve for
x = +5

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1 year ago

Complete combustion of 8.10 g of a hydrocarbon produced 25.9 g of CO2 and 9.27 g of H2O. What is the empirical formula for the h

balu736 [363]

CxHy + O2 --> x CO2 + y/2 H2O

Find the moles of CO2 : 18.9g / 44 g/mol = .430 mol CO2 = .430 mol of C in compound

Find the moles of H2O: 5.79g / 18 g/mol = .322 mol H2O = .166 mol of H in compound

Find the mass of C and H in the compound:

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3 years ago

Which of the following decomposition reactions is/are correct?

Valentin [98]

The generalized reaction for chemical decomposition is: AB → A + B

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2 years ago

4. A 0.51 kg solution contains 87 mg of potassium iodide. Calculate the W/W concentration

anzhelika [568]

Taking into account the definition of percentage composition, the percent composition of potassium iodide in this sample is 0.017%.

<h3>Definition of percent composition </h3>

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

To calculate the percentage of composition, it is necessary to know the mass of the element in a known mass of the compound.

<h3>Percentage Composition in this case</h3>

In this case, you know that a 0.51 kg (or 510000 mg, being 1 kg= 1000000 mg) solution contains 87 mg of potassium iodide.

Dividing the mass amount of potassium iodide present in the compound by the mass of the sample and multiplying it by 100 to obtain a percentage value, the percentage composition of potassium iodide is obtained:

$percentage composition of potassium iodide=\frac{87 mg}{510000 mg} x100$

percentage composition of potassium iodide= 0.017%

Finally, the percent composition of potassium iodide in this sample is 0.017%.

Learn more about percent composition:

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