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3 years ago

1 qt equal to how much ML

Chemistry

1 answer:

Minchanka [31]3 years ago

7 0

Answer:

946.342ML

Explanation:

I'm assuming ML is milliliter.

mL = qt/0.0010567

mL = 1/0.0010567

mL = 946.342

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Consider the following reaction: 2CH3OH(g)  2CH4(g) + O2(g) ΔH = +252.8 kJ a) Calculate the amount of heat transferred when 24.

denpristay [2]

Answer:

For a: The amount of heat transferred for the given amount of methanol is 94.6736 kJ.

For b: The mass of methane gas produced will be 10.384 g.

Explanation:

For the given chemical reaction:

$2CH_3OH(g)\rightarrow 2CH_4(g)+O_2(g);\Delta H=+252.8kJ$

For a:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of methanol = 24.0 g

Molar mass of methanol = 32.04 g/mol

Putting values in above equation, we get:

$\text{Moles of methanol}=\frac{24.0g}{32.04g/mol}=0.749mol$

By Stoichiometry of the reaction:

For every 2 moles of methanol, the amount of heat transferred is +252.8 kJ.

So, for every 0.749 moles of methanol, the amount of heat transferred will be = $\frac{252.8}{2}\times 0.749=94.6736kJ$

Hence, the amount of heat transferred for the given amount of methanol is 94.6736 kJ.

For b:

By Stoichiometry of the reaction:

252.8 kJ of energy is absorbed when 2 moles of methane gas is produced.

So, 82.1 kJ of energy will be absorbed when = $\frac{2}{252.8}\times 82.1=0.649mol$ of methane gas is produced.

Now, calculating the mass of methane gas from equation 1, we get:

Molar mass of methane gas = 16 g/mol

Moles of methane gas = 0.649 moles

Putting values in equation 1, we get:

$0.649mol=\frac{\text{Mass of methane gas}}{16g/mol}\\\\\text{Mass of methane}=10.384g$

Hence, the mass of methane gas produced will be 10.384 g.

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4 years ago

Which property of matter depends on the amount of matter present?

andrew-mc [135]

C.) Volume
Intensive properties, for example; color and density, do not depend on present matter.

8 0

4 years ago

Read 2 more answers

The decarboxylation of oxaloacetate into pyruvate and CO2 at pH 5 and 25C is 10% complete in 5 s, 44% complete in 25 s, 58% comp

sweet [91]

Answer:

The reaction is first order.

Rate constant = 0.021 sec^-1

Explanation:

See the attached file for the explanation.

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3 years ago

A(n)

alex41 [277]

It should be scientific law since a hypothesis is like a prediction and a theory could be used to explain something although it might not be true. There’s many theories just to explain one thing. So it should be scientific law

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3 years ago

What is the percent by volume of ethanol (C2H60, or ethyl alcohol) in the final solution when 90 mL of ethanol is diluted to a v

r-ruslan [8.4K]

Answer:

16.0%.

Explanation:

Volume percent of a substance is the ratio of the substance volume to the solution volume multiplied by 100.

V % of ethanol = (volume of ethanol / volume of the solution) x 100.

volume of ethanol = 90.0 mL, volume of the solution = 550.0 mL.

∴ V % of ethanol = (90.0 mL / 550.0 mL) x 100 = 16.36% ≅ 16.0%.

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3 years ago