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Sergio039 [100]
3 years ago
7

Chemistry !!!!! HELP !!!!!!!!

Chemistry
2 answers:
Len [333]3 years ago
7 0
Inbox me i will explain its easy..
lyudmila [28]3 years ago
3 0
Ill try to help you find the answer
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They neutralize each other

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Imagine that all microorganism suddenly disappeared from earth from what u have learned why do u think that animals would eventu
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What is the overall cell potential for this redox reaction? Ca2+ + 2Li = Ca + 2Li+ Ca2+ + 2e- = Ca -2.87 V Li = Li+ + e- -3.05 V
Jet001 [13]

The redox reaction is

Ca^{+2}  + 2Li(s)  = Ca(s) + 2Li^{+}

Here

Calcium undergoes reduction, and acts as cathode

Lithium undergoes oxidation and acts as anode

The reduction potential of calcium is -2.87 V

The reduction potential of lithium is - -3.05 V

We know that

Ecell = Ecathode - Eanode

Ecell = -2.87 - (-3.05)  = 0.18 V


4 0
3 years ago
Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s
Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

                        N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

where N is amount of radioactive nuclide after t time, N_{0} is initial amount of radioactive nuclide and t_{\frac{1}{2}} is half life of radioactive nuclide

Here N_{0}=4.60 mg, t=4.1\times 10^{9}yr and t_{\frac{1}{2}}=4.5\times 10^{9}yr

So,N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0
3 years ago
A scientist exam in two atoms. One has a nucleus with five protons in five neutron surrounded by five electrons. The other has a
grigory [225]

Answer:

C) They are not made of matter.

Explanation:

Case in which protons are inside of neutrons doesn't exist.

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3 years ago
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