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liberstina [14]
2 years ago
10

The student ran out of time and did not do the second heating. Explain how this error would affect the calculation for the numbe

r of moles
Chemistry
1 answer:
Ber [7]2 years ago
6 0

The error caused will lower the number of moles when he did not do the second heating.This question is related to the empirical formula.

<h3>What is Empirical formula ?</h3>

A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

The empirical formula is the simplest ratio of atoms in a given compound.

we know that heating is used to eliminate most of the water molecules which are attached to the compound in the question, it's given that the second heating was not performed by the students.

This means that there are still some water molecules attached to the compound. This will imply that higher mass will be calculated for the compound because the water molecules are also considered.

So now, if we look at the calculation for the number of moles of water in this, we can say that this will be lower than the actual amount.

This is because there are some unaccounted moles of water which are still attached to the compound and these will be accounted in the compound mass rather than the waters. Therefore, the number of moles will be lower.

Hence, The error caused will lower the number of moles when he did not do the second heating.

Learn more about Empirical formula here ;

https://brainly.in/question/32699671

#SPJ1

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A cube of an unknown metal measures 0.250 cm on one side. The mass of the cube is 0.134 g. Which of the following is most likely
rosijanka [135]

Answer:

8.58 g/cm3

Explanation:

density = mass / volume

be attention that the question gives u the length of

one side of the cube so u should calculate the volume

of the cube using your information of math .

1st we calculate the volume of the cube :

 V of cube = a 3= axaxa

                 = 0.250 x0.250 x0.250

                 = 0.0156 cm3

 2nd step

density = mass/volume

             =  0.134/ 0.0156 = 8.58 g/cm3

5 0
3 years ago
2Na3N3 -&gt; 2Na + 3N2<br><br> if 0.58 mol if NaN3 reacts, what mass of nitrogen would result
Ronch [10]

Answer:

                      Mass = 24.36 g of N₂

Explanation:

                   The balance chemical equation for the decomposition of NaNO₃ is as follow;

                                           2 NaN₃ → 2 Na + 3 N₂

Step 1: Find moles of N₂ as;

According to equation,

                 2 moles of NaNO₃ produces  =  3 moles of N₂

So,

              0.58 moles of NaNO₃ will produce  =  X moles of N₂

Solving for X,

                      X = 3 mol × 0.58 mol / 2 mol

                      X = 0.87 mol of N₂

Step 2: Calculate mass of N₂ as,

Mass = Moles × M.Mass

Mass = 0.87 mol × 28.01 g/mol

Mass = 24.36 g of N₂

8 0
3 years ago
How many grams of H3PO4 are in 175mL of a 2.50M solution of H3PO4?
solmaris [256]
<span>(0.1875 moles)(98.004 g/mole) = 18.37575 g </span>
<span>In correct number of significant figures: 18.4 </span>
5 0
3 years ago
Read 2 more answers
At Jim's auto shop, it takes him minutes to do an oil change and minutes to do a tire change. Let be the number of oil changes h
Juli2301 [7.4K]

Answer:

The total time that Jim needs to change x oil changes and y tire changes is less than 180 min.

The time needed for x oil changes is 12 * x.

The time needed for y tire changes is 18 * y.

The total time is the sum of the above times and needs to be less than 180 that is

12 * x + 18 * y < 180 divide both sides of equation by 6

12/6 * x + 18/6*y < 180/6

2*x + 3*y < 30

2*x < 30 - 3*y divide both sides by 2 to get the inequality for x

x < 30/2 - 3/2*y = 15 - 1.5 y < 15 that is x < = 15

2*x + 3*y < 30

3*y < 30 - 2*x divide both sides by 3 to get the inequality for y

y < 30/3 - 2/3 *x = 10 - 2/3*x < 10 that is y < = 10

Also we can write x + y < x+ 3/2 * y < 15.

Explanation:

Jim's can do not more then 5 oil changes and not more then 10 tire changes or all together she can do not more then 15 total of oil and tire changes.

5 0
3 years ago
Be sure to answer all parts. Consider the reaction N2(g) + 3H2(g) → 2NH3(g)ΔH o rxn = −92.6 kJ/mol If 3.0 moles of N2 react with
Alex787 [66]

Answer:

Work done in Joules = -14865.432J

ΔU = -262.94KJ

Explanation:

The steps are as shown in the attachment

6 0
3 years ago
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