Answer:
(1) Bromination, (2) E2 elimination and (3) epoxidation
Explanation:
- In the first step, -OH group in cyclopentanol is replaced by more facile leaving group Br by treating cyclopentanol with

- In the second step, E2 elimination in presence of strong base e.g. NaOEt/EtOH produce cyclopentene
- In the third step, treatment of cyclopentene with mCPBA produces 1,2-epoxycyclopentane
- Full reaction scheme has been shown below
Answer:
According to Hund's rule and the Aufbau principle in which the orbitals must be filled with electrons, they are not strictly applied in the real universe, because the intermediate and electron-filled atomic orbitals are very stable . Because there are four d-orbitals in universe L, a typical half-full configuration will be xd4 and its full configuration will be xd8, where x is the primary orbital for any specific element. Here is an example:
Vahadium ₂₃V
in real universe: [Ar]₈ 3d³4s²
in universe L: [Ar]₁₈ 3d⁴4s¹
Chromium
in real universe: [Ar]₈ 3d⁵4s¹
in universe L: [Ar]₁₈ 3d⁴4s²
Explanation:
Answer:
<h2>12</h2>
Explanation:
The pH of a solution can be found by using the formula
![pH = - log [ {H}^{+} ]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5B%20%7BH%7D%5E%7B%2B%7D%20%5D)
From the question we have

We have the final answer as
<h3>12</h3>
Hope this helps you
Explanation:
In a magnetic field, the radius of the charged particle is as follows.
r = 
where, m = mass, v = velocity
q = charge, B = magnetic field
Therefore, q will be calculated as follows.
q = 
= 
= 
= 
= +2e
Thus, we can conclude that the charge of the ionized atom is +2e.