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____ [38]
2 years ago
7

If you need to produce 9.75 moles of iron(III) oxide (Fe2O3), how many moles of iron will be required? *

Chemistry
1 answer:
torisob [31]2 years ago
7 0

Answer: Thus 9.75 moles of iron will be required.

Explanation:

The balanced chemical reaction is:

2Fe+3O_2\rightarrow 2Fe_2O_3  

According to stoichiometry :

2 moles of Fe_2O_3 are produced by= 2 moles of Fe

Thus 9.75 moles of Fe_2O_3 are produced by=\frac{2}{2}\times 9.75=9.75moles  of Fe

Thus 9.75 moles of iron will be required.

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By binary codes or a whole image depending on the description of the image.
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2 years ago
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CAN SOMEONE PLEASEE HELPPP
Masja [62]

Answer:

hope its not to late..............Samira's model correctly demonstrates how the properties changed with the rearrangement of the atoms. However not all atoms are accounted for. There is a missing reactant. Samira's model correctly demonstrated how the atoms in two compounds reacted to form two new products. However, the elements present in the reactants side should be the elements that make up the new products in the product side. But as the diagram shows, Sameera has mistakenly added a new element to one of her products which will be wrong.

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8 0
2 years ago
A gas occupies 100 mL at 150. kPa. Find its volume at 200. kPa. You must show all your work to receive credit. Be sure to identi
PtichkaEL [24]

The Boyle-Mariotte's law or Boyle's law is one of the laws of gases that <u>relates the volume (V) and pressure (P) of a certain amount of gas maintained at constant temperature</u>, as follows:

PV = k

where k is a constant.

We can relate the state of a gas at a specific pressure and volume to another state in which the same gas is at different P and V since the product of both variables is equal to a constant, according to the Boyle's law, which will be the same regardless of the state of the gas. In this way,

P₁V₁ = P₂V₂

Where P₁ and V₁ is the pressure and volume of the gas to a state 1 and P₂ and V₂ is the pressure and volume of the same gas in a state 2.

In this case, in the state 1 the gas occupies a volume V₁ = 100 mL at a pressure of P₁ = 150 kPa. Then, in the state 2 the gas occupies a volume V₂ (that we must calculate through the boyle's law) at a pressure of P₂ = 200 kPa.  Substituting these values in the previous equation and clearing V₂, we have,

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