Question

I need help on questions d and e, not sure how to solve!

Answer 1

D.

$m(x) = 0 \\ - 3x = 0 \\ x = 0$

E.

$m(x) = \frac{ - 3}{25}$

$\frac{ - 3x}{x {}^{2} + 2x - 24} = \frac{ - 3}{25}$

$- 3(x {}^{2} + 2x - 24) = - 3(x)(25) \\ divide \: both \: sides \: by - 3$

$x {}^{2} + 2x - 24 = 25x$

$x {}^{2} - 23x - 24 = 0$

$(x - 24)(x + 1) = 0$

$x = 24 \\ x = - 1$

Answer 2

Answer:

D

x=0

Step-by-step explanation:

E)

$\frac{-3x}{x^2+2x-24} =\frac{-3}{25} \\x^2+2x-24=25x\\x^2+2x-25x-24=0\\x^2-23 x-24=0\\x^2-24x+x-24=0\\x(x-24)+1(x-24)=0\\(x-24)(x+1)=0\\x=24,-1$