Answer is: at lower temperatures the reaction rate would decrease.
The lower is the temperature, the slower the reaction becomes.
The Haber process is procedure for the production of ammonia, in this process atmospheric nitrogen (N₂) is converted to ammonia (NH₃):
N₂ + 3H₂ ⇄ 2NH₃ ΔrH = -92 kJ/mol.
Because this is exothermic reaction (enthalpy is less than zero), at lower temperatures, the equilibrium is in favor of ammonia, but the reaction doesn't proceed at a detectable rate.
B. oxidizing
In the reaction the oxidizing agent is reduced.
Answer:
H+(aq) + OH-(aq) ⟶H2O(l)
Explanation:
Step 1: The balanced equation
HCN(aq) + KOH(aq) ⟶ H2O (l) + KCN (aq)
H+(aq) + CN-(aq) + K+(aq) + OH-(aq) ⟶H2O(l) + K+(aq) + CN-(aq)
Step 2: The net ionic equation
The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:
H+(aq) + OH-(aq) ⟶H2O(l)
The answer to this question would be A.
