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Maurinko [17]
2 years ago
15

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What's

Mathematics
1 answer:
lakkis [162]2 years ago
5 0

Answer:

x \leqslant  - 21

Step-by-step explanation:

5(x + 27) \geqslant 6(x + 26)5x + 135 \geqslant 6x + 156

- 21 \geqslant x

x \leqslant  - 21

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Solve each equation using inverse operations: 1. 9w = -54 2. b - 12 = 3 3. n/4 = -11
katovenus [111]

Hello!

Answer:

1. \boxed{W=-6}

*The answer must have A NEGATIVE SIGN ONLY!*

2. \boxed{B=15}

*The answer must have A POSITIVE SIGN ONLY!*

3. \boxed{N=-44}

*The answer must have a NEGATIVE SIGN ONLY!*

Step-by-step explanation:

1. 9w=-54

First, you divide by 9 both sides of an equation.

9w/9=-54/9

Simplify.

-54/9=-6

<u><em>W=-6 is the final answer.</em></u>

____________________________________

2. b-12=3

First you add by 12 both sides of an equation.

b-12+12=3+12

Add by the numbers from left/right.

3+12=15

<u><em>b=15 is the final answer.</em></u>

__________________________________________

3. n/4=-11

First you multiply by 4 both sides of an equation.

4n/4=4(-11)

Multiply by the numbers from left/right.

4*-11=-44

<u><em>n=-44 is the final answer.</em></u>

_____________________________

Hope this helps you!

Have a great day! :)

:D

-Charlie

Thanks!

3 0
3 years ago
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confide
FrozenT [24]

Question:

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$114.00. Assume the population standard deviation is ​$15.30. Construct a​ 90% confidence interval for the population mean.

Answer:

At the 90% confidence level, confidence interval = 110.2484 < μ < 117.7516

At the 95% confidence level, confidence interval = 109.53 < μ < 118.48

The 95% confidence interval is wider

Step-by-step explanation:

Here, we have

Sample size, n = 45

Sample mean, \bar x = $114.00

Population standard deviation, σ = $15.30

The formula for Confidence Interval, CI is given by the following relation;

CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}

Where, z is found for the 90% confidence level as ±1.645

Plugging in the values, we have;

CI=114\pm 1.645 \times \frac{15.3}{\sqrt{45}}

or CI: 110.2484 < μ < 117.7516

At 95% confidence level, we have our z value given as z = ±1.96

From which we have CI=114\pm 1.96 \times \frac{15.3}{\sqrt{45}}

Hence CI: 109.53 < μ < 118.48

To find the wider interval, we subtract their minimum from the maximum as follows;

90% Confidence level: 117.7516 - 110.2484 = 7.5

95% Confidence level: 118.47503 - 109.5297 = 8.94

Therefore, the 95% confidence interval is wider.

8 0
3 years ago
Read 2 more answers
H(x) = 5х+2.0х 3 - 45х-180х.<br> factor the polynomial
poizon [28]
The correct answer is 2x^3-40x-180
4 0
3 years ago
Aline with a slope of contains the point (3.4). The point ( - 2 ) is also on the
Maru [420]

Answer:

Not Sure Without Slope

Step-by-step explanation:

you could use the formula y-y1=m(x-x1)(point slope form) where m is the slope, y1 is the first y point and x1 is the first x point.

For example if a line has slope 3 and passes through the points (5, 6), then the formula you would solve is y-6=3(x-5) to find the equation of the line in slope-intercept form and you should know what to do with everything else.

4 0
3 years ago
Due to weather mark walk to school day of the 20 days in february what would be the fraction representation for the number of da
nekit [7.7K]

Tbe question doesn't state the number of days he walked to school out of 20 school days in the

Month of February.

Answer:

Kindly check explanation

Step-by-step explanation:

To. Obtain the fractional representayion for the number of days he walked to school ;

Let the number of days he walked to school = 10 (this is an hypothesized value)

Number of school days in February = 20

Fraction = 10 /20 = 0.5

The percentage of times walked to school : multiply the fraction obtained above by 100%

0.5 * 100% = 50%

Just put the desired value and proceed uSing the steps described above.

8 0
3 years ago
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