Answer:
Kc = [C2H5OH]/{[C2H4][H2O]}
[H2O] = [C2H5OH]/{[C2H4] x Kc}
[H2O] = 1.69/(0.015 x 9.0 x 10^3) = 0.013 M
Explanation:
Kc is the equilibrium constant, it is egal to the product of the equilibrium concentration of the product dived by the product of the equilibrium concentration of the reactants.
with that formula and what is given, male the equilibrium concentration of H2O the subject of the formula and calculate its concentration by substituting given values.
When iron loses the 2 4s electrons, it attains a valency of +2. Sometimes, iron will also lose one of the paired electrons from 3d orbital, leaving the entire 3d orbital filled with unpaired electrons (which provides a more stable configuration). In this case, its valency will be +3.
Answer:
1.- The energy of a wave will increase the frequency due to the increase in the speed of the wave.
2.- The wavelength will increase if the energy of the wave increases, due to the area that is expand.
3.- A wave with a higher frequency will have faster speed to move.
Explanation:
Wavelength of a wave is due to the speed and the energy that the wavelength carry, so if the energy increases, this quantity of energy need to distribute or in the wavelength or in the frequency, to conduct the wave with a bigger amount of energy.
I need the full question to answer sorry
Answer:
The correct answer is 0.11 mol O₂
Explanation:
The chemical equation for the reaction of acetylene (C₂H₂) with O₂ to produce carbon dioxide (CO₂) and water (H₂O) is the following:
2 C₂H₂(g) + 5 O₂(g) → 4 CO₂(g) + 2 H₂O(g)
The chemical equation is balanced : with the proper estequiometrical coefficients. According to this, 2 moles of C₂H₂ reacts with 5 moles of O₂ to give 4 moles of CO₂ and 2 moles of H₂O.
In order to calculate how many moles of O₂ are needed to produce 0.085 moles of CO₂, we multiply the 0.085 moles of CO₂ by the factor 5 moles O₂/4 moles CO₂ (because 4 moles of CO₂ are produced by 5 moles of O₂ according to the chemical equation):
0.085 moles CO₂ x (5 moles O₂/4 moles CO₂) = 0.10625 moles O₂ = 0.11 moles O₂
