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quester [9]
2 years ago
8

A pendulum can be simply made of a suspended string tied to a weight. If the length of string is measured to be 1 m and the weig

ht is measured to be 0.5 kg, determine its period of oscillation and its frequency of oscillation. Does its period depend on the weight tied to the string?
Physics
1 answer:
Katyanochek1 [597]2 years ago
6 0

The time period of the pendulum is 2 sec, and the frequency will be 0.5 and will on depend on weight of the object.

The time period of a basic pendulum is defined as the time it takes to complete one full oscillation and is indicated by the letter "T".

This concept of frequency leads to the simplest frequency formula

Frequency = 1 / T.

T signifies the time it takes to complete one wave cycle in seconds, while f denotes frequency.

The formula for time period of simple pendulum is

Time Period = 2π√(l/g)

As we can see there is no mass term in the formula, Hence we can say that the time period of simple pendulum will not depend on mass or weight of the object tied to the string.

We have given length as 1 m

Time Period = 2π√(1/9.8)

Time Period = 2π×0.319

Time Period = 2 seconds

Time of the Simple Pendulum is 2 seconds.

Frequency = 1 / Time period

Frequency = 1 / 2

Frequency = 0.5 1/second

Frequency of the Simple Pendulum is 0.5

So we can conclude that the Time period of Simple pendulum is 2π√(l/g) and as we can see there is no term of mass, means the simple pendulum will not be depend on mass or weight. The time period came out to be 2 seconds and the frequency came out to be 0.5.

Learn more about Time Period here:

brainly.com/question/26449711

#SPJ10

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andrey2020 [161]

Answer:

9.8 m/s2

Explanation:

In the first equation above, g is referred to as the acceleration of gravity. Its value is 9.8 m/s2 on Earth. That is to say, the acceleration of gravity on the surface of the earth at sea level is 9.8 m/s2.

Got it from the internet, hope it helps though ^^

7 0
3 years ago
An object travels with a constant speed in a circular path. The net force on the object is
Pepsi [2]

Answer:

toward the center

Explanation:

Before answering, let's remind the first two Newton Laws:

1) An object at rest tends to stay at rest and an object moving at constant velocity tends to continue its motion at constant velocity, unless acted upon a net force

2) An object acted upon a net force F experiences an acceleration a according to the equation

F=ma

where m is the mass of the object.

In this problem, we have an object travelling at constant speed in a circular path. The fact that the trajectory of the object is circular means that the direction of motion of the object is constantly changing: this means that its velocity is changing, so it has an acceleration. And therefore, a net force is acting on it. The force that keeps the object travelling in the circular path is called centripetal force, and it is directed towards the center of the circle (because it prevents the object from continuing its motion straight away).

So, the correct answer is

toward the center

8 0
3 years ago
If a sound wave travels through air at a speed of 345 m/s, what would be the frequency of a 0.80 m long wave?
den301095 [7]

Answer:

D

Explanation:431.3

7 0
3 years ago
A 12.0 g sample of gas occupies 19.2 L at STP. what is the of moles and molecular weight of this gas?​
lubasha [3.4K]

At STP, 1 mole of an ideal gas occupies a volume of about 22.4 L. So if <em>n</em> is the number of moles of this gas, then

<em>n</em> / (19.2 L) = (1 mole) / (22.4 L)   ==>   <em>n</em> = (19.2 L•mole) / (22.4 L) ≈ 0.857 mol

If the sample has a mass of 12.0 g, then its molecular weight is

(12.0 g) / <em>n</em> ≈ 14.0 g/mol

4 0
3 years ago
250 W 12 km/h<br>4. Convert yoor answer from 3 to meters per second.​
taurus [48]

Answer: 3.33 m/s

Explanation:

Assuming the questions is to convert  12 km/h to meter per second (m/s), let's begin:

In order to make the conversion, we have to know the following:

1 km=1000 m

And:

1 h=3600 s

Keeping this in mind, we can make the conversion:

12 \frac{km}{h} \frac{1000 m}{1 km} \frac{1h}{3600 s}

Then:

12 \frac{km}{h}= 3.33 \frac{m}{s}

5 0
3 years ago
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