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vlada-n [284]
3 years ago
15

An object travels with a constant speed in a circular path. The net force on the object is

Physics
1 answer:
Pepsi [2]3 years ago
8 0

Answer:

toward the center

Explanation:

Before answering, let's remind the first two Newton Laws:

1) An object at rest tends to stay at rest and an object moving at constant velocity tends to continue its motion at constant velocity, unless acted upon a net force

2) An object acted upon a net force F experiences an acceleration a according to the equation

F=ma

where m is the mass of the object.

In this problem, we have an object travelling at constant speed in a circular path. The fact that the trajectory of the object is circular means that the direction of motion of the object is constantly changing: this means that its velocity is changing, so it has an acceleration. And therefore, a net force is acting on it. The force that keeps the object travelling in the circular path is called centripetal force, and it is directed towards the center of the circle (because it prevents the object from continuing its motion straight away).

So, the correct answer is

toward the center

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If I traveled 30 miles in 1 hour, then 20 miles in 1 hour, and 50 miles in 3
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Answer:

The answer is 20 miles/hr

Explanation:

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What is the displacement of an object during a specific unit of time.
strojnjashka [21]

Answer:

velocity

Explanation:

the displacement of an object during a specific unit of time.

7 0
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When a fighter pilot feels massive amounts of force when their planes turn quickly applies to_
sattari [20]

Answer:

The answer is A - Newtons First Law

Explanation:

The law is what we call "Inertia". The law basically states that an object wants to stay where it is. We can see the effect from our cars, albeit with less force. When the car turns right, your body goes left, opposite to the turns direction due to us moving position in the car.

3 0
2 years ago
1. A roller coaster car rapidly picks up speed it as it rolls down a slope. As it starts
goldfiish [28.3K]

Answer:

Average acceleration = 6m/s²

Explanation:

Given the following data;

Initial velocity, u = 4m/s

Final velocity, v = 22m/s

Time, t = 3 seconds

To find the average acceleration;

Acceleration = (v - u)/t

Substituting into the equation, we have;

Acceleration = (22 - 4)/3

Acceleration = 18/3

Acceleration = 6m/s²

6 0
3 years ago
A particle of rest energy mc2 is moving with speed v in the positive x direction. The particle decays into two particles, each o
Helga [31]

Answer:

The rest energy of the particle is  mc^2 =  498 MeV

The velocity of the particle is  v = 1.587 *10^8 m/s

Explanation:

From the question we are told that

         The rest energy of the original particle is E = mc^2

         The speed of the particle is  v

         The  rest energy the first  particle is  (mc^2)_1 = 140 MeV1

          The rest energy of the second particle is  (mc^2)_2= 140MeV

         The first particle has a kinetic energy of KE = 282 MeV positive x

           The second particle has a kinetic energy of KE_2 = 25 MeV negative x

           

The total energy of the first  particle is  

             E_1 = (mc^2)_1  + KE_1

Substituting values

           E_1 = 140   +  282

            E_1 =  422 MeV

The total energy of the first  particle is  

             E_1 = (mc^2)_2  + KE_2

             E_1 = 140  + 25

              E_1 =165MeV

The momentum of the first particle can be mathematically evaluated using this expression

           p__{1 }}=  \sqrt{E^2_1 - ((mc^2)_1) ^2}

           p__{1 }}=  \sqrt{422^2 - 140^2}

            p__{1 }}=  398MeV

The final energy of both particle is mathematically evaluated as

             E = E_1 + E_2

             E = 422 + 165

              E = 587 MeV  

The momentum of the first particle can be mathematically evaluated using this expression

           p__{2 }}=  - \sqrt{E^2_2 - ((mc^2)_2) ^2}

The negative sign shows that he direction is  negative x-axis

           p__{2 }}=  -\sqrt{165^2 - 140^2}

            p__{2 }}=  -87MeV

The final momentum of both particle is mathematically evaluated as

                P = p_1 + p_2

    Substituting value  

                P = 398 - 87

                P = 311 MeV

According to the law of conservation of momentum and the conservation of energy the final energy and momentum of both particle must be equal to the initial energy of the original  particle

Then  the rest energy is mathematically represented as

                 mc^2 = \sqrt{E^2 - P^2}

       Substituting values

                 mc^2 = \sqrt{587 ^2 - 311^2}

                  mc^2 =  498 MeV

The velocity of the original particle can be obtained from the mathematical expression as follows

                  v = c\sqrt{1 - [\frac{(mc^2)}{E}]^2 }

Where c is the speed of light with value   c =  3.0 *10^8 m/s

Substituting value

                  v = 3*10^8 *\sqrt{1 - [ \frac{498}{587}] ^2}

                 v = 1.587 *10^8 m/s

8 0
3 years ago
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