An object travels with a constant speed in a circular path. The net force on the object is
1 answer:
Answer:
toward the center
Explanation:
Before answering, let's remind the first two Newton Laws:
1) An object at rest tends to stay at rest and an object moving at constant velocity tends to continue its motion at constant velocity, unless acted upon a net force
2) An object acted upon a net force F experiences an acceleration a according to the equation
where m is the mass of the object.
In this problem, we have an object travelling at constant speed in a circular path. The fact that the trajectory of the object is circular means that the direction of motion of the object is constantly changing: this means that its velocity is changing, so it has an acceleration. And therefore, a net force is acting on it. The force that keeps the object travelling in the circular path is called centripetal force, and it is directed towards the center of the circle (because it prevents the object from continuing its motion straight away).
So, the correct answer is
toward the center
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Answer:
819.78 m
Explanation:
<u>Given:</u>
- OA = range of initial position of the airplane from the point of observation = 375 m
- OB = range of the final position of the airplane from the point of observation = 797 m
= angle of the initial position vector from the observation point =
= angle of the final position vector from the observation point =
= displacement vector from initial position to the final position
A diagram has been attached with the solution in order to clearly show the position of the plane.
Displacement vector of the airplane will be the shortest line joining the initial position of the airplane to the final position of the airplane which is given by:
The magnitude of the displacement vector =
Hence, the magnitude of the displacement of the plane is 819.67 m during the period of observation.
