Answer:
a. Amplitude = 0.244 meters
b. Period = 1.62 seconds
c. Frequency = 0.6173 Hz
Explanation:
a.
With the position goes from 0.122 meters to -0.122 meters (negative because it is in the opposite side of the equilibrium point), the amplitude is the maximum value minus the minimum value:
Amplitude = 0.122 - (-0.122) = 0.122 + 0.122 = 0.244 meters
b.
The period is the amount of time the object takes to arrive in the same position again. So, if it takes 0.81 seconds to go to -0.122 m, it will take another 0.81 seconds to come back to 0.122 m, so the period is the sum of these two times:
Period = 0.81 + 0.81 + 1.62 seconds
c.
The frequency of the movement is the inverse of the period:
Frequency = 1 / Period
So if the period is 1.62 seconds, the frequency is:
Frequency = 1 / 1.62 = 0.6173 Hertz
Answer:
Explanation:
We shall show all given data in vector form and calculate the direction of force with the help of following formula
force F = q ( v x B )
q is charge , v is velocity and B is magnetic field.
Given B = - Bk ( i is right , j is upwards and k is straight up the page )
v = v j
F = q ( vj x - Bk )
= -Bqvi
The direction is towards left .
a ) If velocity is down
v = - v j
F = q ( - vj x - bk )
= qvB i
Direction is right .
b ) v = v i
F = q ( vi x - Bk )
= qvB j
force is upwards
c ) v = - vi
F = q ( -vi x - Bk )
= -qvBj
force is downwards
d ) v = - v k
F = q( - vk x -Bk )
= 0
No force will be created
e ) v = v k
F = q( vk x -Bk )
= 0
No force will be created
Answer:
If you are looking for past papers you can search that up and you will find plenty of resources that will help you out.
E=Eq,
where F is the electrostatic force (or Coulomb force) exerted on a positive test charge q.
