Steven buys a pair of scissors instead of getting a haircut. He belives the scissors will last for a long time, while the haircu
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This question is incomplete, the complete question is;
A beam of white light passes through a uniform thickness of air. If the intensity of the scattered light in the middle of the green part of the visible spectrum (λ=520nm) is I, find the intensity (in terms of I) of scattered light
a) In the middle of the red part of the spectrum (λ= 665 nm)
b) In the middle of the violet part of the spectrum (λ = 420 nm)
Answer:
a) the intensity of scattered light ( in terms of ) In the middle of the red part of the spectrum is 0.3739
b) the intensity of scattered light ( in terms of ) In the middle of the violet part of the spectrum is 2.3497
Explanation:
Given the data in the question,
the visible spectrum (λ=520nm) =
we know that; intensity of scattered light is proportional to 1 / λ⁴
∝ ( 1 / λ⁴ )
so
a)
/
= ( λ / λ
)⁴
As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ is 665 nm
we substitute
/
= ( 520 / 665 )⁴
/
= ( 0.781954887 )⁴
/
= 0.3739
= 0.3739
{ in terms of
}
Therefore, the intensity of scattered light ( in terms of ) In the middle of the red part of the spectrum is 0.3739
b)
/
= ( λ / λ
)⁴
As the middle of the green part of the visible spectrum λ is 520nm and middle of the red part of the spectrum λ is 420 nm
we substitute
/
= ( 520 / 420 )⁴
/
= ( 1.238095 )⁴
/
= 2.3497
= 2.3497
{ in terms of
}
Therefore, the intensity of scattered light ( in terms of ) In the middle of the violet part of the spectrum is 2.3497
Answer:
The electric field outside the sphere will be .
Explanation:
Given that,
Radius of solid sphere = R
Charge = q
According to figure,
Suppose r is the distance between the point P and center of sphere.
If be the volume charge density,
Then, the charge will be,
.....(I)
Consider a Gaussian surface of radius r.
We need to calculate the electric field outside the sphere
Using formula of electric field
Put the value from equation (I)
Hence, The electric field outside the sphere will be .
