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Mrrafil [7]
2 years ago
7

A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.

Physics
1 answer:
Advocard [28]2 years ago
7 0

The potential across the capacitor at t = 1.0 seconds, 5.0 seconds, 20.0 seconds respectively is mathematically given as

  • t=0.476v
  • t=1.967v
  • V2=4.323v

<h3>What is the potential across the capacitor?</h3>

Question Parameters:

A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.

at

  • t = 1.0 seconds
  • 5.0 seconds
  • 20.0 seconds.

Generally, the equation for the Voltage is mathematically given as

v(t)=Vmax=(i-e^{-t/t})

Therefore

For t=1

V=5(i-e^{-1/10})

t=0.476v

For t=5s

V2=5(i-e^{-5/10})

t=1.967

For t=20s

V2=5(i-e^{-20/10})

V2=4.323v

Therefore, the values of voltages at the various times are

  • t=0.476v
  • t=1.967v
  • V2=4.323v

Read more about  Voltage

brainly.com/question/14883923

Complete Question

A 1.0 μF capacitor is being charged by a 5.0 V battery through a 10 MΩ resistor.

Determine the potential across the capacitor when t = 1.0 seconds, 5.0 seconds, 20.0 seconds.

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I = 0.091 A

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U = 0.000165 Joules

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3 years ago
Two cars travel westward along a straight highway, one at a constant velocity of 85 km/h, and the other at a constant velocity o
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To solve letter a:

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d = 115 * 0.71 = 81.65 km.

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2 years ago
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All 2023 Ariya ac synchronous drive motors produce 100% torque at 0 mph for impressive off-the-line acceleration and smooth cruising.

<h3>How to calculate the torque?</h3>

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8 0
2 years ago
During a tennis volley, a ball that arrives at a player at 40 m/s is struck by the racquet and returned at 40 m/s. The other pla
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Answer:Racquet force is twice of Player force

Explanation:

Given

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F_{racquet}=\frac{m(40-(-40))}{\Delta t}

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3 years ago
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RUDIKE [14]
Your equation is:
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An equation is balanced only if there are the same number of atoms of each element on both sides of the arrow - aka same number of atoms of each element in both reactants (left of the arrow) and products (right of the arrow). 

It'll be easiest to tackle this by counting up the number of atoms of each element on the left and on the right and comparing those numbers. If there is a number in front of the entire compound, that means that number applies to all elements in the compound. If the number is a subscript (little number to the right of the element), that means that number only applies to the element that the subscript is attached to:
1) On the left, you have:
2NaOH + H_{2}SO_{4}\\&#10;\\&#10;Na:  \: 2 \: atoms\\&#10;O: \: 2 + 4 = 6 \: atoms\\&#10;H: \: 2 + 2 = 4 \: atoms\\&#10;S:  \: 1 \: atom

2) On the right, you have:
Na_{2}SO_{4} + H_{2}O\\&#10;\\ &#10;Na: \: 2 \: atoms\\ &#10;O: \: 4 + 1 = 5 \: atoms\\ &#10;H: \: 2 \: atoms\\ &#10;S: \: 1 \: atom

You can see that the number of oxygen and hydrogen atoms aren't equal on both the left (reactants) and the right (products), so the equation is unbalanced.

Your final answer is "T<span>he equation is unbalanced because the number of hydrogen atoms and oxygen is not equal in the reactants and in the products."</span>


5 0
3 years ago
Read 2 more answers
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