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Rus_ich [418]
3 years ago
9

Difference between derived quantity and physical quantity​

Physics
1 answer:
Lerok [7]3 years ago
6 0

Answer:

<h2>Derived quantities are based on fundamental quantities, and they can be given in terms of fundamental quantities.</h2>

<h3>Fundamental quantities are the base quantities of a unit system, and they are defined independent of the other quantities. </h3>

Explanation:

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A car is moving eastward and speeding up. The momentum of the car is ______.
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I think the answer is C. Remaining constant
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Calculate the wavelength and frequency at which the intensity of the radiation is a maximum for a blackbody at 298 K. You will n
Juliette [100K]

Answer:

Wavelength, \lambda=9.72\times 10^{-6}\ m

Frequency, f=3.08\times 10^{13}\ Hz

Explanation:

We need to find the intensity of the radiation is a maximum for a black body at 298 K. It can be calculated using Wein's displacement law. It is given by :

\lambda T=2.898\times 10^{-3}\ m-K

\lambda=\dfrac{2.898\times 10^{-3}}{T}

Here, T = 298 K

\lambda=\dfrac{2.898\times 10^{-3}}{298}

\lambda=9.72\times 10^{-6}\ m

If f is the frequency of black body radiation. It is given by :

f=\dfrac{c}{\lambda}

f=\dfrac{3\times 10^8}{9.72\times 10^{-6}}

f=3.08\times 10^{13}\ Hz

Hence, this is the required solution.                                              

6 0
3 years ago
You are driving at 35 m/s east and notice another car that is initially located 462 m in front of you and is moving east at 25 m
GaryK [48]

The easiest way to answer this question is by realizing there are relating the velocities of the two cars. To tackle this problem, you have to understand the picture.  Car 1 travels at 35m/s and Car 2 travels at 25m/s.  Based on relative velocities, we can understand that Car 1 travels 10m/s faster than Car 2 every second.  So we can interpret Car 1's relative velocity to Car 2 as 10m/s.  Car 1 needs to travel 10m/s till a point of catching up to Car 2 which is 462m away.

v = 10m/s

d = 462m

v = d/t

(10) = (462)/t

t = 46.2s

So it takes 46.2 seconds for Car 1 to catch up to Car 2, but the question is asking how far does Car 1 travel to catch up.  So we have to use Car 1's velocity and not the relative velocity:

v = 35m/s

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7 0
4 years ago
Read 2 more answers
______________ controls the flow of electric current.<br> Answer!!! <br> Please
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Answer:

Explanation:

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8 0
3 years ago
A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed pa
AVprozaik [17]

To solve this problem it is necessary to take into account the concepts related to the magnetic moment and the torque applied over magnetic moments.

For the case of the magnetic moment of a loop we have to,

\mu = IA

Where

I = Current

A = Area of the loop

Moreover the torque exerted by the magnetic field is defined as,

\tau = IAB

Where,

I = Current

A = Area of the loop

B = Magnetic Field

PART A) First we need to find the perimeter, then

P = 2\pi r

r = \frac{P}{2\pi}

r = \frac{1.9}{2\pi}

r = 0.3025m,

The total Area of the loop would be given as,

A = \pi r^2

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Substituting at the equation of magnetic moment we have

\mu = (16*10^{-3})(0.287)

\mu = 4.58*10^{-3} A.m^2

Therefore the magnetic moment of the loop is 4.58*10^{-3}Am^2

PART B)  Replacing our values at the equation of torque we have that

\tau = IAB

\tau = (16*10^{-3})(0.287)(0.790)

\tau = 3.62*10^{-3}Nm

Therefore the torque exerted by the magnetic field is 3.62*10^{-3}Nm

6 0
3 years ago
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