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Andreyy89
3 years ago
5

An astronaut spends 3 months in space and then returns to Earth. When she returns to Earth, her muscles have weakened. This is b

ecause of the stronger gravitational force that was exerted on her muscles in space.
true or false
Physics
2 answers:
Pepsi [2]3 years ago
6 0
False. there's less gravitational force in space than on earth
SIZIF [17.4K]3 years ago
3 0
False. Her muscles weakened because of the WEAKER force of gravity in space. Muscles are one of those things that if you don't yoozum, you loozum. Your brain is another one.
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Convert 10095 mm to pm​
ludmilkaskok [199]

Answer:

1.01 × 1013 picometres

Explanation:

multiply the length value by 1e+9

3 0
3 years ago
A steel beam that is 5.50 m long weighs 332 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending
ElenaW [278]

Explanation:

The given data is as follows.

    Length of beam, (L) = 5.50 m

    Weight of the beam, (W_{b}) = 332 N

     Weight of the Suki, (W_{s}) = 505 N

After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.

                 \sum M_{o} = 0

     -W_{s} \times x + W_{b} \times 1.5 = 0

                x = \frac{W_{b} \times 1.5}{W_{s}}

                   = \frac{332 N \times 1.5}{505 N}

                   = 0.986 m

Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.

Thus, we can conclude that suki can come 1.014 m close to the end before the beam begins to tip.

8 0
4 years ago
a 250g moves eastward along a straight path at a constant velocity of 12 m per second calculate the momentum of the ball ​
lara31 [8.8K]

Explanation:

If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .

6 0
3 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
nalin [4]

Answer:

The maximum volume is 1417.87 inch^3

Explanation:

<u>Optimization Using Derivatives</u>

We have a 24x30 inch piece of metal and we need to make a rectangular box by cutting a square from each corner of the piece and bending up the sides. The width of the piece is 24 inches and its length is 30 inches

When we cut a square of each corner of side x, the base of the box (after bending up the sides) will be (24-2x) and (30-2x), width and length respectively. The volume of the box is

V=(24-2x)(30-2x)x

Operating

V=4x^3-108x^2+720x

To find the maximum value of V, we compute the first derivative and equate it to zero

V'=12x^2-216x+720=0

Simplifying by 12

x^2-18x+60=0

Completing squares

x^2-18x+81-81+60=0

(x-9)^2=21

We have two values for x

x=9+\sqrt{21}=13.58\ inch

x=9-\sqrt{21}=4.42\ inch

The first value is not feasible because it will produce a negative width (24-2(13.58))=-6.16

We'll keep only the solution

x=4.42\ inch

The width is

w=(24-2(4.42))=15.16\ inch

The length is

l=(30-2(4.42))=21.16\ inch

And the height

x=4.42\ inch

The maximum volume is

V=(15.16)(21.16)(4.42)=1417.87\ inch^3

4 0
3 years ago
The magnetic field of a straight, current-carrying wire is:
frutty [35]
Conductive current is the answer I d k
5 0
2 years ago
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