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navik [9.2K]
3 years ago
14

An electron is located in an electric field of magnitude 600. newtons per coulomb. what is the magnitude of the electrostatic fo

rce acting on the electron?
Physics
1 answer:
SOVA2 [1]3 years ago
6 0
The magnitude of the electrostatic force acting on a charge q is the product between the charge and the intensity of the electric field E. The magnitude of the electron charge is q=1.6 \cdot 10^{-19}C (we are not interested in the sign), so the electrostatic force magnitude is
F=qE=(1.6 \cdot 10^{-19}C)(600 N/C)=9.6\cdot 10^{-17}N
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An insulating sphere is 8.00 cm in diameter and carries a 6.50 µC charge uniformly distributed throughout its interior volume.
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Explanation:

(a)   Formula to calculate the density is as follows.

            \rho = \frac{Q}{\frac{4}{3}\pi a^{3}}

                       = \frac{6.50 \times 10^{-6}}{\frac{4}{3} \times 3.14 \times (0.04)^{3}}

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                      = 2.42 \times 10^{-2} C/m^{3} \times 4.1762 \times (0.01)^{3}

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(b)  For r = 6.50 cm, the value of charge will be calculated as follows.

                q_{in} = \frac{Q}{\frac{4}{3}\pi a^{3}}

                          = \frac{6.50 \times 10^{-6}}{\frac{4}{3} \times 3.14 \times (0.065)^{3}}

                          = 7.454 \mu C

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3 years ago
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3 years ago
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