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Answer:
3441.6 grams.
Explanation:
2 O₃ → 3 O₂
First we <u>convert 71.7 moles of ozone (O₃) into moles of oxygen gas (O₂)</u>, using the <em>stoichiometric coefficients</em> of the reation:
71.7 mol O₃ * = 107.55 mol O₂
Then we <u>convert 107.55 moles of O₂ into grams</u>, using the <em>molar mass of O₂</em>:
107.55 mol * 32 g/mol = 3441.6 g
Answer : The final temperature of gas will be, 149 K
Explanation :
Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.
or,
where,
= initial volume of gas = 1.55 L
= final volume of gas = 753 ml = 0.753 L
= initial temperature of gas =
= final temperature of gas = ?
Now put all the given values in the above formula, we get the final temperature of the gas.
Therefore, the final temperature of gas will be, 149 K