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wolverine [178]
3 years ago
6

How many bonded pairs of electrons are there in the molecule NOCl? A)2 B)3 C)4 D)5

Chemistry
1 answer:
iren2701 [21]3 years ago
3 0
There are 2 covalent bonds between the Nitrogen and Oxygen, and 1 between the Nitrogen and Chlorine. 

It should be 3.
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How much heat is required to take a 150 g sample of water from 10.0 ℃ to 95.0 ℃? cs,water = 4.184 J/g*℃
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Answer don't know at all but i will find out by tomorrow

Explanation: sorry

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Which of the following is not the same as 8,540 centigrams?
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Answer:

8.54 hg

because the other three is equvilent

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2. Have someone hold the mirror for you, slowly move at least 3 m away from the it.
Ahat [919]

Answer: Slowly move at least 3 m away from the side mirror. Observe your image as you ... Compare the images formed in different mirrors. ... but if i stand 3m away, even though there is no light, it reflects the other material it can ... is transparent so you cannot see yourself much in the mirror, that is my observation.

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3 years ago
Is there a relationship between low-income neighborhoods and obesity? What do you think are some of the reasons?
pickupchik [31]

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cheaper foods are usually more processed and unhealthy, therefore, poorer people are likelier to be obese.

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6 0
3 years ago
Calculate the molality of a solution containing 22.75 g of glycerol (C3H8O3) in 79.6 g of ethanol (C2H5OH).
3241004551 [841]

Answer:

3.11 mol/kg

Explanation:

Molality M = number of moles of solute, n/mass of solvent, m

To calculate the number of moles of glycerol (C₃H₈O₃) in 22.75 g of glycerol, we find its molar (molecular) mass, M',

So, M' = 3 × atomic mass of carbon + 8 × atomic mass hydrogen + 3 × atomic mass of oxygen

= 3 × 12 g/mol + 8 × 1 g/mol + 3 × 16 g/mol = 36 g/mol + 8 g/mol + 48 g/mol = 92 g/mol.

So, number of moles of glycerol, n = m'/M' where m' = mass of glycerol = 22.75 g and M' = molecular mass of glycerol = 92 g/mol

So, n = m'/M'

n = 22.75 g/92 g/mol

n = 0.247 mol

So, the molality of the solution M = n/m

Since m = mass of ethanol = 79.6 g = 0.0796 kg, substituting the value of n into the equation, we have

M = 0.247 mol/0.0796 kg

M = 3.11 mol/kg

So, the molality of the solution is 3.11 mol/kg.

5 0
3 years ago
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