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GarryVolchara [31]
2 years ago
13

A binomial experiment has the given number of trials N and the given success probability P.

Mathematics
1 answer:
yan [13]2 years ago
8 0

The probability of the success will be 0.3826.

<h3>What is binomial distribution?</h3>

Bernoulli's trials are those trials which end up randomly either on success (with probability p) or on failures (with probability 1- p = q (say))

The probability that out of n trials, there'd be x successes is given by

\rm P(x) = \: ^nC_xp^x(1-p)^{n-x}

We have

n = 8

p = 0.1

q = 1 – 0.1 = 0.9

x = 1

Then we have

P(1) = ⁸C₁ x (0.1)¹ x (0.9)⁷

P(1) = 0.3826

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

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(b) factorise <br>(3m-1)(6-a)-(m+3)(6-a)​
Step2247 [10]

Answer:

Step-by-step explanation:

(3m-1)(6-a)-(m+3)(6-a)

=3m(6-a)-1(6-a)-m(6-a)+3(6-a)

=18m-3ma-6+a-6m+ma+18-3a

=12m-2ma+12-2a

=2(6m-ma+6-a)

7 0
3 years ago
Translate the equation 49 is what percent of 66?​
mamaluj [8]

Answer:

49 ÷ 66 × 100= x

Step-by-step explanation:

5 0
2 years ago
Sandra is making the shape of a rhombus. The first three angles are 75°, 75°, and 105°. What is the measure of the fourth angle?
mrs_skeptik [129]
Its 105° because the rhombus is essentially a square or rectangle of sorts and at least 2 sides have to be alike 
3 0
3 years ago
Read 2 more answers
A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 178 students
xxTIMURxx [149]

Answer:

critical value = 1.645

The 90% confidence interval = ( -22.62, -17.58)

Step-by-step explanation:

Given that:

the sample  size n_1 = 178

the sample size n_2 = 226

the sample mean \overline x_1 = 54.4

the sample mean \overline x_2 = 74.5

population standard deviation \sigma_1 = 18.58

population standard deviation \sigma_2 = 9.52

level of significance ∝ = 1 - 0.90 = 0.10

The critical value for Z_{\alpha/2} = Z _{0.10/2} = Z_{0.005} is 1.645

For the construction of our confidence interval, we use 90% since that is used to find the critical value.

∴

The margin of error = Z \times\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}

1.645 \times\sqrt{\dfrac{18.58^2}{178} + \dfrac{9.52^2}{226}}

1.645 \times\sqrt{\dfrac{345.2164}{178} + \dfrac{90.6304}{226}}

1.645 \times\sqrt{2.34042}

\simeq 2.52

The lower limit = ( \overline x_1 - \overline x_2) - (M.O.E)

= ( 54.4-74.5) - (2.52)

= -20.1 - 2.52

= -22.62

The upper limit = ( \overline x_1 - \overline x_2) + (M.O.E)

= ( 54.4-74.5) + (2.52)

= -20.1 + 2.52

= -17.58

The 90% confidence interval = ( -22.62, -17.58)

6 0
3 years ago
A family buys 3 dinners at $9 each, 2 kids’ meals at $4 each, and 4 desserts at $3 each. After using a $10 off coupon, how much
Tomtit [17]
Hi

3 dinners at $9 each.
9 x 3

2 kids' meals at $4 each
9 x 3 + 4 x 2

4 desserts at $3 each
9 x 3 + 4 x 2 + 4 x 3

$10 dollar off coupon
9 x 3 + 4 x 2 + 4 x 3 - 10

Solve using PEMDAS
9 x 3 + 4 x 2 + 4 x 3 - 10 = ?
27 + 8 + 12 - 10 = ?
35 + 12 - 10 = ?
47 - 10 = ?
37

The answer is 37

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
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