Answer:
A - right shift
B - no shift
C - right shift
Explanation:
<em>According to Le Chatelier's principle, when a reaction is in equilibrium and one of the factors affecting the rate of reaction is introduced, the equilibrium will shift so as to annul the effects of the constraint. </em>
In this case, decreasing the volume of the reaction's container is equivalent to increasing the pressure of the reaction. When pressure is increased, the reaction will shift towards the side with a lower number of moles.
In A, the total number of moles on the left-hand side of the reaction is two while it is one on the right-hand side. <em>An increase in pressure will, therefore, see the equilibrium shifting to the right-hand side.</em>
In B, the total number of moles on both the right and the left-hand side is two each. <em>An increase in the pressure will have no effect on the equilibrium.</em>
In C, the total number of moles on the left-hand side is two while it is one on the right-hand side. <em>Hence, an increase in the pressure of the reaction will cause a shift in the equilibrium to the right. </em>