Answer:
Postulate: Gas particles are extremely small and are far apart.
The activities can be used to demonstrate the postulate is :
<u>Observing colored gas spreading into an inverted jar placed on top of a jar containing the gas</u>
<u />
Explanation:
colored gas spreading into an inverted jar placed on top of a jar containing the gas:
This occur because of two reasons:
1. <em><u>The Gaseous particles are largely spaced . There is large distance between the gases molecule</u></em>
<em><u>2. The gases are in continuous motion . Hence they posses very high kinetic energy . This is the reason they mixes quickly if placed in a jar.</u></em>
<em><u>This occur by the process of diffusion. </u></em>
Diffusion of Gases: The intermixing of particles from the region of high concentration to low concentration.
The coloured gas goes into the space between the gaseous molecule present in the jar.(Gases are far apart)
As soon as the coloured gas is mixed in the jar , It spread quickly by diffusion because , The gaseous particles are extremely small and are far apart.
Answer:
24.5872 meters per second
Rouned 24.6 or 25
Answer:
Aluminium (Al): (3*2)+(5*2)=16
Sulphor (S): (3*1)=3
Oxygen (O): (4*3)+(3*1)=15
Answer:
18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
Explanation:
Mercury oxide has molar mass of 216.6 g/ mol. It gas a molecular formula of HgO.
The decomposition of mercury oxide is given by the chemical equation below:
2HgO ----> 2Hg + O₂
2 moles of HgO decomposes to produce 1 mole of Hg
2 moles of HgO has a mass of 433.2 g
433.2 g of HgO produces 216.6 g of Hg
18.0 of HgO will produce 18 × 216.6/433.2 g of Hg = 9.0 g of Hg
Therefore, 18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
