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3 years ago

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53. Which of the following is NOT a correct interpretation of CH2O, the formula of the compound formaldehyde?

1 answer:

Free_Kalibri [48]3 years ago

7 0

Answer:

B There are two grams of hydrogen for each gram of carbon in this compound.

Explanation:

The second option is a wrong interpretation of this chemical representation of formaldehyde.

Formaldehyde is an organic compound with the formula CH₂O.

As this is the simplest formula of the compound, it is the empirical formula. Also, the formula is the actual one for the compound and it is the molecular formula.

Chemically, the formula shows 1 mole of carbon, 2 moles of H and 1 mole of oxygen in the compound.

A mole of a substance is more a less a unit of measurement in chemistry and it is the amount of substance that contains the avogadro's number of particles.

This ratio is not the mass of chemical species in the compound. You cannot tell the mass of elements in a compound by merely looking at the formula.

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Determine the mass of 2.75 moles of CaSO4. Record your work and your answer.

maw [93]

Explanation:

$RFM \: = 160 \: g \\ 1 \: mole \: weighs \: 160 \: g \\ 2.75 \: moles \: weighs \: \frac{2.75 \times 160}{1} g \\ = 440 \: g$

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3 years ago

Give an example of a change that the ecosystem was able to recover from and return to equilibrium.

Tanzania [10]

Answer:

The Fox is at the top of the food chain; so, the other animals could increase in population and the fox could return

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2 years ago

The solubility of carbon dioxide in water is 0.161 g CO2in 100 mL of water at 20ºC and 1.00 atmCO2. A soft drink is carbonated w

Sedbober [7]

<u>Answer:</u> The solubility of carbon dioxide at 5.50 atm is $0.886g/100mL$

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{A}=K_H\times p_{A}$

Or,

$\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}$

where,

$C_1\text{ and }p_1$ are the initial concentration and partial pressure of carbon dioxide

$C_2\text{ and }p_2$ are the final concentration and partial pressure of carbon dioxide

We are given:

$C_1=0.161g/100mL\\p_1=1.00atm\\C_2=?\\p_2=5.50atm$

Putting values in above equation, we get:

$\frac{0.161g/100mL}{C_2}=\frac{1.00atm}{5.50atm}\\\\C_2=\frac{0.161g/100mL\times 5.50atm}{1.00atm}=0.886g/100mL$

Hence, the solubility of carbon dioxide at 5.50 atm is $0.886g/100mL$

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3 years ago

How to get ice and snow<br> power?

algol13

Answer:

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3 years ago

The density of water is 1.00 g/ml at 4°c. how many water molecules are present in 2.56 ml of water at this temperature?

o-na [289]

Answer:

8.55 × 10²² Molecules

Solution:

Step 1: Calculate the Mass of Water as;

Density = Mass ÷ Volume

Solving for Mass,

Mass = Density × Volume

Putting values,

Mass = 1 g.mL⁻¹ × 2.56 mL

Mass = 2.56 g

Step 2: Calculate Moles of Water as,

Moles = Mass ÷ M.Mass

Putting values,

Moles = 2.56 g ÷ 18 g.mol⁻¹

Moles = 0.142 mol

Step 3: Calculate Number of Molecules of Water as,

# of Molecules = Moles × 6.022 × 10²³

Putting value of mole,

# of Molecules = 0.142 × 6.022 × 10²³

# of Molecules = 8.55 × 10²² Molecules

5 0

3 years ago