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gtnhenbr [62]
3 years ago
14

Let f(x)= 8x^3 - 28x + 61 and g(x) = 2x+5. fins f(x) over g(x).

Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0
8x^3-28x+61/2x+5

4x^2-10x+11 with a remainder of 6 

Not sure if there is supposed to be a remainder but there is one 
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With reference to the figure, sin X equals?<br> 1.) 0.250<br> 2.)0.447<br> 3.)0.894<br> 4.)1
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Answer:

3.) 0.894

Step-by-step explanation:

✔️First, find BD using Pythagorean Theorem:

BD² = BC² - DC²

BC = 17.89

DC = 16

Plug in the values

BD² = 17.89² - 16²

BD² = 64.0521

BD = √64.0521

BD = 8.0 (nearest tenth)

✔️Next, find AD using the right triangle altitude theorem:

BD = √(AD*DC)

Plug in the values into the equation

8 = √(AD*16)

Square both sides

8² = AD*16

64 = AD*16

Divide both sides by 16

4 = AD

AD = 4

✔️Find AB using Pythagorean Theorem:

AB = √(BD² + AD²)

AB = √(8² + 4²)

AB = √(64 + 16)

AB = √(80)

AB = 8.9 (nearest tenth)

✔️Find sin x using trigonometric ratio formula:

Reference angle = x

Opposite side = BD = 8

Hypotenuse = AB = 8.944

Thus:

sin(x) = \frac{opp}{hyp} = \frac{8}{8.944} = 0.894 (nearest thousandth)

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